Answer:
Explanation:
Let's break it down:
- Butane- A 4 carbon alkane
- Methyl - A CH₃ group
- 2,2 - Both the Methyl groups are attached at carbon 2
We can now draw the structure of 2,2-dimethyl butane using the following steps:
- Draw the backbone (butane)
- Draw the substituents (2 methyl groups at carbon 2)
Answer:
0.940mol &
0.000301mol respectively.
Explanation:
number of moles = given mass / molar mass
given mass of Nacl = 55g Molar mass = 23 + 35.5
n=m/M = 55g/58.5g/mol = 0.940mol
note- (add the atomic weights of sodium and chlorine to get the molar mass of Nacl.) = 58.5g/mol
similarly, NaCO3 = 23 + 12 + 16*3 = 83g/mol
n=m/M = 0.025g/83g/mol = 3.01 * 10^-4 = 0.000301mol
extra: If you ever get asked to put it in number of particles just use the relation of 1mole = 6.02 * 10^23 particles.
Answer:
RNA
Explanation:
The nucleic isolated was quantified by 2 types of fluorescent dyes, which binds only to specific type of nucleic acid. You can find the information on the specificity of dyes on your labsheet or dye supplier's website. For our dyes, however:
- SyBr Green II only emits fluorescent light when it binds to RNA or Single Strand DNA
- PicoGreen only fluoresce when bound to Double Strand DNA
With these information, we know that our nucleic acid is either single strand DNA or RNA, however, it is also mentioned that
"Nucleic acid was isolated by lysing cells in detergent, guanidine isothiocyanate, and DNAse"
DNAse, which is an enzyme that breaks down DNA, destroys any extracted DNA during the process, thus, the only possible nucleic acid we have isolated is RNA
Answer: True
Explanation:
Titration is a quantitative technique where a solution of known concentration is used to determine the concentration of an unknown solution. The titrant (the known solution) is added from a burette to a known quantity of the the unknown solution until the reaction is complete.
By knowing the volume of titrant, we can determine the concentration of the unknown.
Thus the statement Titrations provide a method of quantitatively measuring the concentration of an unknown solution is True .
