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Alex
3 years ago
11

1.5 moles are present in 60.0 grams of calcium.

Chemistry
1 answer:
Andrew [12]3 years ago
3 0

Answer:

True.

Explanation:

To know which option is correct, let us calculate the number of mole present in 60g of calcium. This is illustrated below:

Mass of Ca = 60g

Molar Mass of Ca = 40g/mol

Number of mole Ca =....?

Number of mole = Mass/Molar Mass

Number of mole of Ca = 60/40

Number of mole Ca = 1.5 moles.

From the calculations made above, we can see that 1.5 moles are present in 60.0 grams of calcium

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emmasim [6.3K]
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The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
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Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

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CH_4 +H_2O \to  3H_2+ CO \ (g)

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3 years ago
45.0 g of Ca(NO3)2 are used to create a 1.3 M solution. What is the volume of the solution
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                                       M = moles / V 
Solving for V,
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Also, moles is equal to,
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puting value of moles from eq. 2 into eq. 1,
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Putting values,
                                       V = (45 g / 164 g/mol) / 1.3 mol/dm³

                                       V = 0.21 dm³ 
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