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MaRussiya [10]
3 years ago
11

HELPP!!!! URGENT!!!!

Physics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

How Urgent are we talking?

Explanation:

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A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre
ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined  using equation of motion

S=ut+\frac{1}{2}  at^2

where u is the initial velocity which is zero here

t is time taken, a is acceleration due to gravity

the position of  first drop after time t is given by

S_{1}  =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)

the position of  next drop at same time is

S_{2}  =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)

distance between them is S_{1} -S_{2}  is a(t-1)

from the above the difference will increase with the time

3 0
3 years ago
One problem caused by technology is that of pollution true or false
HACTEHA [7]

Answer:

True, because tech is what creates thing like cars and other veicals (i know i spelled it wrong)

hope this helps

Explanation:

5 0
3 years ago
Read 2 more answers
A stone tumbles into a mine shaft and strikes bottom after falling for 4.2 second how deep is the mine shaft
rjkz [21]
4.2*9.8\\41.16

41.16 meters
5 0
3 years ago
Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each tra
vredina [299]

Answer:

At low pressure- \mu_{k}=0.02315

At high pressure- \mu_{k}=0.00445

Explanation:

Initial speed, V_{i}=3.3 m/s

Final speed, V_{f}=3.3/2= 1.65 m/s

Net horizontal force due to rolling friction F_{net}=\mu_{k} mg where m is mass, g is acceleration due to gravity, \mu_{k} is coefficient of rolling friction

From kinematic relation, V_{f}^{2}- V_{i}^{2}=2ad

For each tire,

V_{f}^{2}- V_{i}^{2}=2\mu_{k}gd

Making \mu_{k} the subject

\mu_{k}=\frac {V_{f}^{2}- V_{i}^{2}}{2gd}

Under low pressure of 40 Psi, d=18 m

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*18}=-0.02315

Therefore, \mu_{k}=0.02315

At a pressure of 105 Psi, d=93.7

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*93.7}=-0.00445

Therefore, \mu_{k}=0.00445

4 0
3 years ago
Julia can swim at 3.5 km/h in still water. She attempts to head straight north
raketka [301]

1) 3.7 km/hr  N19°W

2) she must aim at N20°E

work sheet  #6

relative velocity

3 0
3 years ago
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