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3 years ago

6

Displacement vectors of 3 m and 5 m in the same direction combine to ma

1 answer:

andrey2020 [161]3 years ago

6 0

Answer:

The magnitude of the displacement vector will be 8 meters.

Explanation:

Given the vectors:

r= 3 m

s= 5 m

The resulting vector is the sum of the vectors r and s. When we add vectors, the vectors that point in the same direction are added and the vectors that point in opposite directions are subtracted. Therefore, the result will be:

R= r + s = 3 m + 5 m = 8 m

The resulting vector will be 8 m in magnitude and the same direction as the previous vectors.

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Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.

Mars2501 [29]

Answer:

$0.5\times 10^{-6}C$

Explanation:

According to coulombs law force between two charges is given by $F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}$ here R is the distance between both the charges which is given as 25 cm

We have given force F =0.036 N

So $0.036=\frac{1}{4\pi \times 8.85\times 10^{-12}}\frac{Q^2}{(0.25^2)}$ As $\epsilon _0$ is constant which value is $8.85\times 10^{-12}$

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$Q=0.5\times 10^{-6}C$

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2 years ago

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A source produces 20 crests and 20 troughs in 4 seconds. The second crest is 3 cm away from the first crest.Calculate :

sineoko [7]

Answer:

Solution given:

No of waves[N] =20crests & 20 troughs

=20waves

Time[T]=4seconds

distance[d]=3cm=0.03m

Now

<u>Wave</u><u> </u><u>length</u><u>=</u>3cm=3 × ${10}^{ - 2}m$

<u>Frequency</u>= $\frac{No of waves}{time}$

= $\frac{20}{4}$ =5Hertz

and

Wave speed:wave length×frequency=3 × ${10}^{ - 2}m$ ×5=1.5 × ${10}^{ - 1} \tt{ {ms}^{ - 1}}$ .

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2 years ago

A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilomet

pshichka [43]

Answer:

The average speed for the entire run is 12 km/h.

Explanation:

The average speed is given by the following equation:

$\overline{v} = \frac{d_{T}}{t_{T}}$

Where:

$d_{T}$ : is the total distance

$t_{T}$ : is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

$d_{T} = 13 km + 5 km = 18 km$

$t_{T} = 1 h + \frac{1}{2} h = 1.5 h$

Hence, the average speed is:

$\overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h$

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!

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