Answer:
Molarity = 3.46 M
Explanation:
Given data:
Percentage of silver nitrate = 40.0%
Density of AgNO₃ = 1.47 g/mL
Molarity of solution = ?
Solution:
40% means out of 100g we have 40 g of AgNO₃ and 60g solvent.
Number of moles of silver nitrate = mass /molar mass
Number of moles = 40 g/ 170 g/mol
Number of moles = 0.235 mol
Volume of solution:
Total mass of solution = 100 g
density = 1.47 g/mL which means there are 1.47 gram into 1 mL.
100 g/1 × 1mL/ 1.47 g × 1 L / 1000 mL
0.068 L
Molarity:
Molarity = number of moles / volume in L
Molarity = 0.235 mol / 0.068 L
Molarity = 3.46 M
