The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is
C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is
6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)
Using the equation for the standard enthalpy change of formation
ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}
C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
= -1273.3 - (0 + 0 + 0)
= -1273.3
Answer:
2.5 mol Cl2 will react with 5 mol Na.
Explanation:
D — density
hope this helps !
Answer: The size of actual bed is 75 inches
Explanation: Scale refers to the ratio of the original dimension to the dimension on paper (miniaturised dimension). Since it is a ratio, it has no dimension.
Scale= original dimension/miniaturised dimension
Given that scale is 1:25
It means that every 1 inch on paper would correspond to 25 inches in reality.
The length of the model bed= 3 inches
Hence, the length of the original bed is 25*3 = 75 inches
