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3 years ago

An aqueous solution is 40.0% by mass silver nitrate, AgNO3, and has a density of 1.47 g/mL.

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

3 0

Answer:

Molarity = 3.46 M

Explanation:

Given data:

Percentage of silver nitrate = 40.0%

Density of AgNO₃ = 1.47 g/mL

Molarity of solution = ?

Solution:

40% means out of 100g we have 40 g of AgNO₃ and 60g solvent.

Number of moles of silver nitrate = mass /molar mass

Number of moles = 40 g/ 170 g/mol

Number of moles = 0.235 mol

Volume of solution:

Total mass of solution = 100 g

density = 1.47 g/mL which means there are 1.47 gram into 1 mL.

100 g/1 × 1mL/ 1.47 g × 1 L / 1000 mL

0.068 L

Molarity:

Molarity = number of moles / volume in L

Molarity = 0.235 mol / 0.068 L

Molarity = 3.46 M

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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?

Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

We have the following data:

Vo (initial volume) = 1.00 L

V (final volume) = 473 mL → 0.473 L

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)

P (final pressure) = ? (in atm)

We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:

$P_0*V_0 = P*V$

$1*1 = P*0.473$

$1 = 0.473\:P$

$0.473\:P = 1$

$P = \dfrac{1}{0.473}$

$\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The new pressure of the gas is 2.11 atm

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$\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

3 0

3 years ago

A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution

MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the pH formula:

$pH~=~-Log[H_3O^+]$

By definition, the pH value is calculated when we do the -Log of the concentration of the hydronium ions ( $H_3O^+$ ). So, the next step is the calculation of the concentration of the hydronium ions. For this, we have to use the molarity formula:

$M=\frac{mol}{L}$

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

$M=\frac{0.0231~moles}{3.33~L}=0.00693~M$

With this value, now we can calculate the pH value:

$pH~=~-Log[0.00693~M]~=~2.15$

The pH would be 2.15

I hope it helps!

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2 years ago