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Ratling [72]
3 years ago
13

What is the wavelength of a radio photon from an "AM" radio station that broadcasts at 1520 kilohertz? And what is its energy?

Physics
1 answer:
DiKsa [7]3 years ago
8 0

Given parameters:

Frequency of the wave  = 1520kHz   = 1520 x 10³Hz

Unknown:

Wavelength of the radio photon = ?

Energy of the wave = ?

Solution:

The wavelength of any electromagnetic wave can found using the expression below;

          C = f x ∧

Where C is the velocity of light  = 3 x 10⁸m/s

            f is the frequency of the wave

            ∧ is the wavelength

Since the unknown is ∧, input the known parameters and solve for it;

       3 x 10⁸  = 1520 x 10³  x ∧

    Wavelength  = \frac{3 x 10^{8} }{1520 x 10^{3} }  

   Wavelength  = \frac{3 x 10^{8} }{1.52 x 10^{6} }

  Wavelength  = 1.97 x 10²m

ii. Energy of the wave;

        Energy of a wave  = hf

where h is the planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹

           f is the frequency of the wave

Input the parameters and solve;

            Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶

                                               = 10.1 x 10⁻²⁸J

The energy of this wave is 10.1 x 10⁻²⁸J

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astra-53 [7]

Answer:

D. provide the most compelling evidence of cause-and-effect relationships.

Explanation:

3 0
3 years ago
In a mass spectrometer used for commercial purposes, uranium ions of mass 3.76 X 10^(-25) kg and charge 3.5 X 10^(-19) C are sep
Flauer [41]

Answer:

a. 0.394 T b. 0.255 A c. 1.309 × 10⁸ J

Explanation:

Here is the complete question

A certain commercial mass spectrometer (Fig. 28-12) is used to separate uranium ions of mass 3.92 x 10-25 kg and charge 3.20 x 10-19 C from related species. The ions are accelerated through a potential difference of 109 kV and then pass into a uniform magnetic field, where they are bent in a path of radius 1.31 m. After traveling through 180° and passing through a slit of width 0.752 mm and height 0.991 cm, they are collected in a cup. (a) What is the magnitude of the (perpendicular) magnetic field in the separator? If the machine is used to separate out 1.12 mg of material per hour, calculate (b) the current (in A) of the desired ions in the machine and (c) the thermal energy (in J) produced in the cup in 1.31 h.

Solution

a. The magnitude of the (perpendicular) magnetic field in the separator

The kinetic energy of the uranium ions = electric potential energy

¹/₂mv² = qV

v = √(2qV/m) where v = speed of uranium ions, q = uranium ion charge = 3.2 × 10⁻¹⁹ C , m = mass of uranium ions = 3.92 × 10⁻²⁵ kg and V = 109 kV = 1.09 × 10⁵ V

v = √(2qV/m) = √(2 × 3.2 × 10⁻¹⁹ C × 1.09 × 10⁵ V/3.92 × 10⁻²⁵ kg)

v = 4.22 × 10⁵ m/s

Also, the magnetic force on the uranium ions equals the centripetal force when it passes through the magnetic field.

Bqv = mv²/r

B = mv/rq   where B = magnetic field strength and r = radius of circle = 1.31 m

B = m(√(2qV/m))/rq

B = √(2mV/q)/r

B = √(2 × 3.92 × 10⁻²⁵ kg × 1.09 × 10⁵ V/3.2 × 10⁻¹⁹ C)/1.31 m

B = √0.26705/1.31

B = 0.394 T

(b) the current (in A) of the desired ions in the machine

Since a mass m of 3.92 × 10⁻²⁵ kg of uranium ions carries a charge q of 3.2 × 10⁻¹⁹ C, then 1.12 mg per hour = 1.12 × 10⁻³ kg/h. In 1.31 h, our mass is M = 1.12 × 10⁻³ kg/h × 1.31 h = 1.47 × 10⁻³ kg carries a charge of Q of

m/q = M/Q

Q = Mq/m

Q = 1.47 × 10⁻³ kg × 3.2 × 10⁻¹⁹ C/3.92 × 10⁻²⁵ kg

Q = 1200 C

The current i = Q/t where t = time = 1.31 h = 1.31 × 60 × 60 s = 4716 s

i = 1200/4716

i = 0.2545 A

i ≅ 0.255 A

(c) the thermal energy (in J) produced in the cup in 1.31 h.

The thermal energy produced in the cup equals the kinetic energy lost by the uranium ions hitting the cup in 1.31 h.

E = ¹/₂Mv² = ¹/₂ × 1.47 × 10⁻³ kg × (4.22 × 10⁵ m/s)²

E = 1.309 × 10⁸ J

3 0
3 years ago
Do heavier objects fall more slowly than lighter objects?
aksik [14]
Think of it like this, gravity has to pull harder on the heavier object to make them fall at the same rate , but doesn't have to pull as hard for the lighter object , thus is why sometimes heavier objects fall faster then lighter ones
8 0
4 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a frictionless floor. He decides to move them
Anit [1.1K]

Answer:

2.8 N

Explanation:

Fp = 7.7 N

mA = 12.1 kg

mB = 7 kg

Let a be the acceleration and Fc be the contact force between A and B.

By the free body diagram, use Newton's second law

Fp - Fc = mA x a ..... (1)

Fc = mB x a ..... (2)

Adding both the equations

Fp = (mA + mB) x a

7.7 = (12.1 + 7) x a

a = 0.4 m/s^2

Substitute this value in equation (2), we get

Fc = 7 x 0.4 = 2.8 N

Thus, the contact force between the two blocks is 2.8 N.

Explanation:

3 0
3 years ago
1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es
bezimeni [28]

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

7 0
3 years ago
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