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Marat540 [252]
3 years ago
12

What do waves carry from place to place​

Chemistry
1 answer:
mario62 [17]3 years ago
3 0

Answer:

Waves carry energy from place to place.

Explanation:

Some waves are used for mainly communication and phone signals. They help people get internet in the middle of nowhere if you are near an energy wave.

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Which transition metals are paramagnetic but can easily form ferromagnetic alloys with other metals?
Brrunno [24]

Answer: Paramagnetism is most easily observed in the salts of some of the first row transition metals (manganese through nickel). The se metal ions have unpaired electrons in degenerate d orbitals as predicted by Hund's rule and thus exhibit paramagnetism.

Explanation: METALS ARE ELECTRONS

AND PARAMAGNETIC OBSERVES SALT FORST ROWS ONLY

6 0
3 years ago
How do scientists think the activity of the "Siberian Traps" changed the chemistry of the oceans?
luda_lava [24]
Am so sorry I don’t know how to help you hope you find the answer
7 0
3 years ago
How does Cancer Begin?
pickupchik [31]

Answer:

Cancer is a disease caused when cells divide uncontrollably and spread into surrounding tissues.

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3 0
4 years ago
In each of the following diatomic molecules, which end of the molecule is positive relative to the other end?
docker41 [41]

Answer:

A- Hydrogen Fluoride, HF

3 0
3 years ago
Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
4 years ago
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