a) cross out 11mL from list 1, 2 mL from list 2, and 998 cm3 from list 3.
b) circle 200 mL from list 1, 801 mL from list 2, and 1 L from list 3.
Answer:
C. 3CO(g) + Fe2O3(s)
Explanation:
The substance(s) to the hath left of the arrow in a chemical equation art hath called reactants. A reactant is a substance yond is presenteth at the starteth of a chemical reaction. The substance(s) to the right of the arrow art hath called products. A product is a substance yond is presenteth at the endeth of a chemical reaction
So in this example, 3CO(g) + Fe2O3(s) art the reactants.
The 2Fe(S) + 3CO2(G) art the products.
Desire I holp! Has't a most wondrous day!
Hope I helped! Have a great day!
answer:
as per the formula of given carbohydrate the answer is 15 moles
explanation:
- 1 mole carbohydrate contains 6 moles water
- 2.5 moles contain 6 X 2.5 = 15 moles
Answer:
1.47 atm
Explanation:
Step 1: Given data
- Initial volume (V₁): 32.4 L
- Initial pressure (P₁): 1 atm (standard pressure)
- Initial temperature (T₁): 273 K (standard temperature)
- Final volume (V₂): 28.4 L
- Final temperature (T₂): 352 K
Step 2: Calculate the final pressure of the gas
We can calculate the final pressure of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
P₂ = P₁ × V₁ × T₂ / T₁ × V₂
P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm