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liberstina [14]
2 years ago
10

A SCUBA tank can normally hold 18 liters of gas at 3000 psi. How many liters of gas would this be equivalent to if the gas were

at 14.7 psi?
Chemistry
1 answer:
NikAS [45]2 years ago
5 0

Liters of gas at 14.7 psi: 3674 L

Explanation:

We can solve this problem by using Boyle's law, which states that:

"For an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

pV=const.

where

p is the gas pressure

V is its volume

This law can also be rewritten as

p_1 V_1 = p_2 V_2

Where:

p_1 = 3000 psi is the initial pressure of the gas

V_1 = 18 L is the initial volume of the gas

p_2 = 14.7 psi is the final pressure of the gas

V_2 is the final volume

Therefore, we can calculate the volume of gas corresponding to 14.7 psi of pressure:

V_2=\frac{p_1 V_1}{p_2}=\frac{(3000)(18)}{14.7}=3674 L

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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Answer:

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Explanation:

Cl₂ is above Br₂ in the activity series.

Bromine will not displace chlorine from its salts.

The reaction will not occur.

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In addition to not causing damage to the sample, what is another advantage of using a microspectrophotometer to analyze fibers?
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Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

<h3>What is a microspectrophotometer?</h3>

Microspectrophotometry is a biological technique used to measure the absorption or transmission spectrum of a solid or liquid material in either transmitted or reflected light.

Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.

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What is the formula for tin(IV) sulfide?<br> A. Sn4S<br> B. SnS2<br> C. Sns<br> D. SnS4
defon

Answer:

SnS_{2}

Explanation:

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If you transfer energy into two substances which one would melt first
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The following diagrams represent mixtures of NO(g) and O2(g). These two substances react as follows: 2NO(g)+O2(g)→2NO2(g) It has
Alja [10]

This is an incomplete question, here is a complete question and an image is attached below.

The following diagrams represent mixtures of NO(g) and O₂(g). These two substances react as follows:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

It has been determined experimentally that the rate is second order in NO and first order in O₂.

Based on this fact, which of the following mixtures will have the fastest initial rate?

The mixture (1). The mixture (2). The mixture (3).

Answer : The mixture 1 has the fastest initial rate.

Explanation :

The given chemical reaction is:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate law expression is:

Rate=k[NO]^2[O_2]

Now we have to determine the number of molecules of NO\text{ and }O_2

In mixture 1 : There are 5 NO and 4 O_2 molecules.

In mixture 2 : There are 7 NO and 2 O_2 molecules.

In mixture 3 : There are 3 NO and 5 O_2 molecules.

Now we have to determine the rate law expression for mixture 1, 2 and 3.

The rate law expression for mixture 1 is:

Rate=k[NO]^2[O_2]

Rate=k(5)^2\times (4)

Rate=k(100)

The rate law expression for mixture 2 is:

Rate=k[NO]^2[O_2]

Rate=k(7)^2\times (2)

Rate=k(98)

The rate law expression for mixture 3 is:

Rate=k[NO]^2[O_2]

Rate=k(3)^2\times (5)

Rate=k(45)

Hence, the mixture 1 has the fastest initial rate.

4 0
3 years ago
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