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Fittoniya [83]
3 years ago
14

A bromodichlorobenzene which gives four signals in the broadband proton-decoupled 13C spectrum could be:

Chemistry
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

See explanation

Explanation:

In this question, we can have <u>several possibilities</u> for the bromodichlorobenzene that depends on the position of the Br and Cl in the benzene. Our options are:

<u>a) 2-bromo-1,3-dichlorobenzene</u>

<u>b) 1-bromo-2,4-dichlorobenzene</u>

<u>c) 1-bromo-2,3-dichlorobenzene</u>

<u>d) 1-bromo-2,3-dichlorobenzene</u>

<u>e) 4-bromo-1,2-dichlorobenzene</u>

See figure 1

Now, if only have 4 signals, we will have only 4 different types of carbons. In benzene we have 6 carbons, therefore, we will have <u>symmetry</u> in the molecule and some of the carbons would be equivalent. The only molecule that has symmetry is "<u>2-bromo-1,3-dichlorobenzene</u>" because we have several carbons with the same neighbors (<u>see figure 2</u>).

Finally, to check the molecule we can check the 13C NMR for 2-bromo-1,3-dichlorobenzene and we will see that only have 4 signals (<u>see figure 3</u>)

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