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Fynjy0 [20]
3 years ago
15

How many moles of nitrogen, N, are in 0.286 mil of ammonium nitrate?

Chemistry
1 answer:
Arisa [49]3 years ago
8 0

Answer:

0.572

Explanation:

The formula for ammonium nitrate is

NH4NO3

The trick here is to realize the 4 applies only to the hydrogen. The 3 applies only to the oxygen.

There are 2 nitrogens in the formula. So if the entire molecule represents 0.286 mols. The individual mols of each part of the formula is just multiplied by the number of moles of the molecule. In formula form

Number of moles of the atoms making up the molecule = number of atoms from the formula * mols of the molecule.

2*0.286 = 0.572 moles of Nitrogen

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Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?
mylen [45]

Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is  the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

Therefore, Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

4 0
3 years ago
Wich of these equations are balanced? a) H2SO4+2AL---&gt;AL2(SO4) b)2KCL+Pb(NO3)2---&gt;2KNO3+PbCL2
Zolol [24]

The answer is b since on a it says H2 but on the right side there is no H idk if you forgot to put H there so im guessing b. Have a good day

4 0
3 years ago
Thallium has two stable isotopes, 203tl and 205tl. knowing that the atomic weight of thallium is 204.4, which isotope is the mor
Elza [17]
You have to figure out a way to write the two unknown abundances in terms of one variable.

The total abundance is 1 (or 100%). So if you say the abundance for the first one is X then the abundance for the second one has to be 1-X (where X is the decimal of the percentage so say 0.8 for 80%).

203(X) + 205(1-X) = 204.4

Then you just solve for X to get the percentage for TI-203.
And then solve for 1-X to get the percentage for TI-205.

After that the higher percentage would be the most abundant.

203x + 205 - 205x = 204.4
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x = 0.3
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Then the TI-205 would have the highest percentage and would be the most abundant.
7 0
3 years ago
An someone help me with this
valina [46]

2)c

3)b

4)c

5)a

hope this helps!!!

6)a

7)c

3 0
3 years ago
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