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Fynjy0 [20]
3 years ago
15

How many moles of nitrogen, N, are in 0.286 mil of ammonium nitrate?

Chemistry
1 answer:
Arisa [49]3 years ago
8 0

Answer:

0.572

Explanation:

The formula for ammonium nitrate is

NH4NO3

The trick here is to realize the 4 applies only to the hydrogen. The 3 applies only to the oxygen.

There are 2 nitrogens in the formula. So if the entire molecule represents 0.286 mols. The individual mols of each part of the formula is just multiplied by the number of moles of the molecule. In formula form

Number of moles of the atoms making up the molecule = number of atoms from the formula * mols of the molecule.

2*0.286 = 0.572 moles of Nitrogen

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You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution
Ostrovityanka [42]

Answer:

145 grams of a 0.480 % KCN solution contains 697 mg of KCN.

Explanation:

w/w % : The percentage mass or fraction is mass of the of solute present in 100 grams of the solution.

w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

given =  w/w% = 0.480 %

Mass of solute that KCN = 697 mg = 0.697 g

(1 mg = 0.001 g)

Mass of the solution = ? = x

0.480\%=\frac{0.697 g}{x}\times 100

x=\frac{0.697 g}{0.480}\times 100

x = 145.21 g ≈ 145 g

145 grams of a 0.480 % KCN solution contains 697 mg of KCN.

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3 years ago
You have prepared a saturated solution of x at 20∘c using 39.0 g of water. how much more solute can be dissolved if the temperat
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Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g

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