A heat pump is a device used to heat something, in this case water. Heat pump takes heat from colder object and transfers it to warmer object. This is opposite to <span>direction of spontaneous heat transfer which from warmer to colder object.
In this problem a room got colder while water got warmer. This is due to work done by heat pump. This is what is described in correct answer c).
a) is not correct because it shows </span>direction of spontaneous heat transfer. It also says that <span>Aleksei’s family purchased a new water heater and in description givne in a) it would mean that water got colder.
b) is not correct because if the </span><span>burning fuel increased the thermal energy in the air it would mean that this room got warmer than rest of house.
d) is not correct because burning fuel does not absorb </span><span>thermal energy. It releases it.</span>
Answer:
A fuse and circuit breaker both serve to protect an overloaded electrical circuit by interrupting the continuity, or the flow of electricity. ... Fuses tend to be quicker to interrupt the flow of power, but must be replaced after they melt, while circuit breakers can usually simply be reset.
Answer:
B can take 0.64 sec for the longest nap .
Explanation:
Given that,
Total distance = 350 m
Acceleration of A = 1.6 m/s²
Distance = 30 m
Acceleration of B = 2.0 m/s²
We need to calculate the time for A
Using equation of motion
![s=ut+\dfrac{1}{2}at_{A}^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat_%7BA%7D%5E2)
Put the value in the equation
![30=0+\dfrac{1}{2}\times1.6\times t_{A}^2](https://tex.z-dn.net/?f=30%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1.6%5Ctimes%20t_%7BA%7D%5E2)
![t_{A}=\sqrt{\dfrac{30\times2}{1.6}}](https://tex.z-dn.net/?f=t_%7BA%7D%3D%5Csqrt%7B%5Cdfrac%7B30%5Ctimes2%7D%7B1.6%7D%7D)
![t_{A}=6.12\ sec](https://tex.z-dn.net/?f=t_%7BA%7D%3D6.12%5C%20sec)
We need to calculate the time for B
Using equation of motion
Put the value in the equation
![30=0+\dfrac{1}{2}\times2.0\times t_{B}^2](https://tex.z-dn.net/?f=30%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes2.0%5Ctimes%20t_%7BB%7D%5E2)
![t_{B}=\sqrt{\dfrac{30\times2}{2.0}}](https://tex.z-dn.net/?f=t_%7BB%7D%3D%5Csqrt%7B%5Cdfrac%7B30%5Ctimes2%7D%7B2.0%7D%7D)
![t_{B}=5.48\ sec](https://tex.z-dn.net/?f=t_%7BB%7D%3D5.48%5C%20sec)
We need to calculate the time for longest nap
Using formula for difference of time
![t'=t_{A}-t_{B}](https://tex.z-dn.net/?f=t%27%3Dt_%7BA%7D-t_%7BB%7D)
![t'=6.12-5.48](https://tex.z-dn.net/?f=t%27%3D6.12-5.48)
![t'=0.64\ s](https://tex.z-dn.net/?f=t%27%3D0.64%5C%20s)
Hence, B can take 0.64 sec for the longest nap .
<em>Answer: </em>tellurium (Te)
<em>atomic number = 52 ,</em>
<em>Number of energy levels = 5;</em>
First energy level = 2
Second energy level = 8
Third energy level = 18
Fourth energy level = 18
Fifth energy level = 6
<em>In this electron configuration, 0uter most electrons are 6.</em>
Answer:
As beams of particles and their associated energy are given off, the pulsar will lose energy slowly, which will decrease the rate of its rotation. The frequency of pulses would therefore decrease, so that fewer pulses are observed in a given time span. The strength of the pulse signal will also decrease so the pulses will become fainter. Eventually, the pulsar should rotate so slowly and have such a low emission of radiation that it would no longer be observable.