Answer:
Because of the location, humidity and temperatures.
Explanation:
Coca is grown in humid and very humid subtropical forests, called yungas and
they form the lower floor of the upper Jungle, in the Central Andes, mostly in Peru and Bolivia. The yungas are in contact with the rainforests of the lowlands in Amazonia, where it has been started to expand coca cultivation recently (Dourojeanni, 1988). The optimum altitude is 1000 a 2000 meters (where cocaine content is higher), with optimal annual average precipitation, is 2000 meters mm, but it is grown between 700 and 2000 msnm and with an average annual rainfall of 1000 to 4200 mm.
msnm = meters above sea level
Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive
Answer:
The correct option is;
C. 1,715 m
Explanation:
We are given the information from the group of teen at the City edge
Time of arrival of explosion sound = 5 s after sighting
Time of sighting explosion = 5 s before hearing the boom
Speed of sound in air ≈ 343 m/s
Speed of light = 299,792 km/s
Therefore, distance covered by sound in 5 seconds is given by the following equation;
Hence Distance = 343 m/s × 5 s = 1715 m
To check, we compare the time it would take for the light to cover 1715 m
That is 
which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.
Therefore, the distance of the students from the factory is approximately 1,715 m
