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Tatiana [17]
3 years ago
11

When turned on, a fan requires 5.0 seconds to get up to its final operating rotational speed of 1200 rpm. a) How large is the fi

nal operating angular speed, in rad/s? b) What was the angular acceleration of the fan, in rad/s^2?
Physics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

a)

125.6 rad/s

b)

25.12 rad/s²

Explanation:

a)

t = time required by the fan to get up to final operating speed = 5 sec

w = final operating rotational speed = 1200 rpm

we know that :

1 revolution = 2π rad

1 min = 60 sec

w = 1200\frac{rev}{min}\frac{2\pi rad}{1 rev}\frac{1 min}{60 sec}

w = \frac{1200\times 2\pi }{60}\frac{rad}{s}

w = 125.6 rad/s

b)

w₀ = initial angular speed = 0 rad/s

α = angular acceleration

using the equation

w = w₀ + α t

125.6 = 0 + α (5)

α = 25.12 rad/s²

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Answer:

Explanation:

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r₁₂ = 8 cm , r₂₃ = 4 cm , r₁₃ = 4 cm.

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Potential energy  =  9 x 10⁹ x [ - 400 x 10⁻¹⁸ / .08  +  -200x10⁻¹⁸ / .04 +  200 x 10¹⁸ / .04 ]

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9 x 10⁹ [ 20 x 10⁻⁹ / .05 + - 20 x 10⁻⁹ / .05 + 10 x 10⁻⁹ / .03 ]

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<h2>hope it helps</h2><h2>stay safe healthy and happy....</h2>
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