1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Keith_Richards [23]
3 years ago
7

What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic

le as it travels through water (which has an index of refraction of n
Physics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

2.3*10^8m/s

Explanation:

Using

V = c/n

Where c= speed of light

n = refractive index of water

By substituting

We have

V= 3*10^8m/s/1.33

= 2.3*10^8m/s

You might be interested in
Short note on types of errors​
jonny [76]

Answer:what errors

Explanation:

Need more information

5 0
3 years ago
Read 2 more answers
An electric generator contains a coil of 140 turns of wire, each forming a rectangular loop 71.2 cm by 22.6 cm. The coil is plac
Montano1993 [528]

Answer:

11405Volt

Explanation:

To solve this problem it is necessary to use the concept related to induced voltage or electromotive force measured in volts. Through this force it is possible to maintain a potential difference between two points in an open circuit or to produce an electric current in a closed circuit.

The equation that allows the calculation of this voltage is given by,

\epsilon = BAN \omega

Where

B = Magnetic field

A= Area

N = Number of loops

\omega= Angular velocity

Our values previously given are:

N = 140

A = 71.2*10^{-2}m*22.6*10^{-2}m=0.1609m^2

B = 4.32 T

\omega = 1120 rev / min

We need convert the angular velocity to international system, then

\omega = 1120 rev/min

\omega = 1120rev/min*\frac{2\pi}{1rev}*\frac{1min}{60sec}

\omega = 117.2rad/s

Applying the equation for emf, we replace the values and we will obtain the value.

\epsilon = BAN \omega

\epsilon = (4.32)(0.1609)(140)*117.2

\epsilon = 11405Volt

4 0
4 years ago
5.00-kg particle starts from the origin at time zero. Its velocity as a function of time is given by v =6t^2 i + 2t j where v is
otez555 [7]

The concept of derivatives and integrals allows to find the results for the questions are the motion of a particle where the speed depends on time are:

       a)the position is:  r = 2 t³ i + t² j

       b) the position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

       c) The acceleration is: a = 12 t i + 2 j

       d) the force is: F = 60 t i + 10 j

       e) the torque is:  τ = 40 t³ k^

       f) tha angular momentum is:  L = 4t³ - 6 t² k^

       g) The kinetic energy is: K = 2 m t² (9t² +1)

       h) The power is:   P = 2m (36 t³ + 2t)

Kinematics studies the movement of bodies, looking for relationships between position, speed and acceleration.

a) They indicate the function of speed.

        v = 6 t² i + 2t j

Ask the function of the position.   The velocity is defined by the variation of the position with respect to time

          v = \frac{dr}{dt}  

          dr = v dt

we substitute and integrate.

        ∫ dr = ∫ (6 t² i + 2t j) dt

        r - 0 = 6 \frac{t^3 }{3} \ \hat i + 2 \frac{t^2}{2 \ \hat j }  

       r = 2 t³ i + t² j

b) The position of the body on the y axis is a parabola and on the x axis it is a cubic function.

c) Acceleration is defined as the change in velocity with time.

           a = \frac{dv}{dt}  

           a = \frac{d}{dt} \ (6t^2 i + 2t j)  

           a = 12 t i + 2 j

d) Newton's second law states that force is proportional to mass times the body's acceleration.

          F = ma

          F = m (12 t i + 2 j)

          F = 5 12 t i + 2 j

          F = 60 t i + 10 j

e) Torque is the vector product of the force and the distance to the origin.

           τ = F x r

The easiest way to write these expressions is to solve for the determinant.

         \tau = \left[\begin{array}{ccc}i&j&k\\F_x&F_y&F_z\\x&y&z\end{array}\right]  

        \tau = \left[\begin{array}{ccc}i&j&k\\60t &10&0\\2t^3 &t^2&0\end{array}\right]  

       τ = (60t t² - 2t³ 10) k

       τ = 40 t³ k ^

f) Angular momentum

        L = r x p

        L =rx (mv)

        L = m (rxv)

The easiest way to write these expressions is to solve for the determinant.

       \left[\begin{array}{ccc}i&j&k\\2t^3 &t^2&0\\6t^2&2t&0\end{array}\right]  

    L = (4t³ - 6 t²) k

 

g) The kinetic energy is

            K = ½ m v²

            K = ½ m (6 t² i + 2t j) ²

            K = m 18 t⁴ + 2t²

            K = 2 m t² (9t² +1)

h) Power is work per unit time

           P = \frac{dW}{dt}dW / dt

The relationship between work and kinetic energy

           W = ΔK

     

          P = 2m \ \frac{d}{dt} ( 9 t^4 + t^2)

          p = 2m (36 t³ + 2t)

In conclusion with the concept of derivatives and integrals we can find the results for the questions are the motion of a particle where the speed depends on time are:

       a) The position is:  r = 2 t³ i + t² j

       b) The position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

       c) The acceleration is: a = 12 t i + 2 j

       d) The force is: F = 60 t i + 10 j

       e) The torque is:  τ = 40 t³ k^

       f) The angular momentum is:  L = 4t³ - 6 t² k^

       g) The kinetic energy is: K = 2 m t² (9t² +1)

       h) The power is:   P = 2m (36 t³ + 2t)

Learn more here:  brainly.com/question/11298125

8 0
2 years ago
Read 2 more answers
Two persons A and B do same amount of work. The person A does that work in t1sec and the person b in t2sec. Find the ratio of po
MissTica

The ratio between power of A and power of B is 2

Explanation:

In physics, power is defined as the ratio between the work done and the time taken to do the work:

P=\frac{W}{t}

where

P is the work done

t is the time taken

In this problem, we have:

Person A and person B do the same amount of work --> let's call this work W

Person A does this work in a time of t_A = 1 s, so the power delivered by A is

P_A = \frac{W}{1}=W

Person B does this work in a time of t_B = 2 s, so the power delivered by B is

P_B = \frac{W}{2}

So, the ratio of the powers delivered by the two persons is

\frac{P_A}{P_B}=\frac{W}{W/2}=2

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

4 0
3 years ago
Determine the kinetic energy of a 55kg woman running with the velocity of 5.87m/s
Greeley [361]
The formula for kinetic energy = ½m·v<span>2

1/2 * 55 kg x 5,87 m/s ^2 = 27.5 x </span>34.4569 = <span>947.56475 Joule </span>≈ 948 J
4 0
4 years ago
Other questions:
  • 70.0 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck slapped at him at a velocity of 35.0 m/s. Suppose
    6·2 answers
  • The p wave on an electrocardiogram represents __________.
    12·1 answer
  • A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic
    13·1 answer
  • Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slid
    9·1 answer
  • A 2.5 kg block starts with a speed of 3 m/s, goes down a 4 m hill, and then slides up a new hill but stops when it is only 1.5 m
    13·1 answer
  • The engine that moves the cables for the San Francisco cable cars delivers 390.3 kW of power for each line. How long does it tak
    6·1 answer
  • With explanation pls
    8·1 answer
  • I need this done asap no links !!!<br> this is a science question
    5·1 answer
  • The ability of a telescope to separate two closely spaced stars is called _____.
    8·1 answer
  • A 45 N force acts on a 8.45 kg object at rest. How fast will the object accelerate on a frictionless surface?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!