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strojnjashka [21]
4 years ago
9

An example of hydrogen bonding would be the attractions between outer hydrogen atoms and the central nitrogen atom within the NH

3 molecule.
TRUE

FALSE
Chemistry
2 answers:
marshall27 [118]4 years ago
7 0

Answer:

The answer to your question is: false.

Explanation:

Hydrogen bonding is tha attraction of hydrogen atoms to the oxygen or nitrogen of a different molecule not between the atoms of the same molecule.

So this description of hydrogen bonding is incorrect.

White raven [17]4 years ago
4 0
Completely false, hydrogen bonding occurs only between hydrogen and oxygen atoms.
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Compute the value of the molar heat capacity at constant volume, CVCV, for CO2CO2 on the assumption that there is no vibrational
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Answer:

Explanation:

Molar heat capacity at constant volume Cv  of a gas = n x .5 R where n is degree of freedom of the gas molecules

CO₂ is a linear molecule , so number of degree of freedom =  3 + 2 = 5

3 is translational and 2 is rotational degree of freedom . There is no vibrational degree of freedom given .

So Cv = 5 / 2 R

= 2.5 R .

4 0
3 years ago
Why does sulfur have a higher melting point than phosphorus
tiny-mole [99]
Because phosphorus is more flammable than sulfur!

Have a nice day! :)

5 0
4 years ago
What pressure will be necessary to compress 2 liters of a gas at 1 atm to a volume of 0.05 liters if the temperature remains con
PtichkaEL [24]
<h3>Answer:</h3>

40 atm

<h3>Explanation:</h3>
  • According to Boyle's law, the pressure and the volume of a fixed mass of a gas are inversely proportional at constant absolute temperature.
  • That is; P\alpha \frac{1}{V}
  • At varying pressure and volume,

P1V1 =P2V2

In this case,

Initial volume, V1 = 2 L

Initial pressure, P1 = 1 atm

New volume, V2 = 0.05 L

We are required to calculate the new pressure,

Rearranging the formula;

P2 = P1V1 ÷ V2

     = (1 atm × 2L) ÷ 0.05 L

     = 40 atm

Therefore, the pressure required is 40 atm

8 0
3 years ago
What would happen to the block if it had a density of 0.500 kg/L and was placed in the same 100.0 L tank of water?
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I’m not sure if there was important information in the question before this one, but the answer based on the info I have is B.

The density of water is 1kg/L. Since the density of the block is less, it will float.
6 0
4 years ago
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TLDR: the answer is C. 22,920 years.

Half-life describes the amount of time for a radioactive substance to decay to one-half of the original substance’s weight. So, if we had 100g of C-14, after 5,730 years, only 50g remain; after another 5,730 years, only 25g would remain, and so on.

In this problem, we are meant to assume that the original amount of C-14 was 64g, and that, through decay, it forms N-14. We can figure out how many half lives have passed by figuring out how much 4 is out of 64 by dividing 64 by two repeatedly. Each time, count a half life.

64 - 32 (1 HL) - 16 (2 HL) - 8 (3 HL) - 4 (4 HL)

In this problem, 4 half lives have passed. We can now multiply this by the time for one half life to find how many years have passed.

4 x 5,730 = 22,920 years

Approximately 22,920 years have passed since the drawing was created.
6 0
3 years ago
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