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2 years ago

Fill in the blank spaces using the names of the two-dimensional figures listed below.

Mathematics

1 answer:

S_A_V [24]2 years ago

8 0

Explanation:

There are many versions of the taxonomy diagram for quadrilaterals. The details depend on the particulars of the definitions you use. Here, we'll say a parallelogram is a subset of trapezoids. Not all authors would agree.

(2) kite -- two pairs of adjacent same-length sides

(3) trapezoid -- (at least one) pair of parallel opposite sides

(4) parallelogram -- opposite sides are parallel

(5) rhombus -- all sides the same length (and opposite sides parallel)

(6) rectangle -- parallel opposite sides and right angles

(7) square -- same-length parallel opposite sides and right angles

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the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur

natita [175]

Answer:

The width of the frame is equal to $8\ cm$

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

$(28-2x)(32-2x)=192$

$896-56x-64x+4x^{2} =192$

$4x^{2}-120x+704=0$

Simplify

$x^{2}-30x+176=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-30x+176=0$

$a=1\\b=-30\\c=176$

substitute in the formula

$x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}$

$x=\frac{30(+/-)\sqrt{196}} {2}$

$x=\frac{30(+/-)14} {2}$

$x=\frac{30+14} {2}=22\ cm$ ----> this solution is not logic

$x=\frac{30-14} {2}=8\ cm$

The width of the frame is equal to $8\ cm$

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3 years ago

An airplane travels at a speed of 960 km/h how for can it travel in 1 hour

Marat540 [252]

Answer:

960 km

Step-by-step explanation:

Speed = Distance/Time.

From the question, we are to find the Distance.

The formula for Distance is given as:

Speed × Time.

From the question:

Speed = 960 km/hr

Time = 1 hour

Distance = 960 km/hr × 1 hour

Distance = 960 km

Therefore, the airplane can travel for 960km in 1 hour

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2 years ago

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Assoli18 [71]

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2 years ago

HELP!!!!

KIM [24]

Answer:

102,000

Step-by-step explanation:

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2 years ago

Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 8 when x is less than 0

mariarad [96]

Find Lim f(x) as x->0

for

f(x)=5x-8 ......x<0

f(x)=|-4-x|......x ≥ 0

Clearly

f(0)=|-4-0|=|-4|=4 exists.

The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8

The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4

Since the left and right limits do not both equal f(0), the limit does not exist.

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2 years ago

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