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3 years ago

A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is done?

Physics

1 answer:

malfutka [58]3 years ago

4 0

Answer:

The answer to your question is: W = 2063.4 J

Explanation:

Data

Force = 157 N

angle = 25°

distance = 14.5 m

W = ?

Process

- Find the horizontal force

cos Ф = adjacent side / hypotenuse

adjacent side = hypotenuse x cosФ

a.s. = 157 x cos 25

a. s. = 142.3 N

- Find the work

W = F x d

W = 142.3 x 14.5

W = 2063.4 J

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A 50gk boy on a rough horizontal ground the coefficeint of static friction is 0.68

Soloha48 [4]

Given that,

Mass of a boy = 50 kg

The coefficient of static friction = 0.68

To find,

Let us assume we need to find the maximum static friction between the boy and the ground.

Solution,

The formula for the maximum static friction between the two objects is given by :

$F=\mu N$

Where

N is normal force

Substitute all the values,

$F=0.68\times 50\times 10\\\\F=340\ N$

Therefore, the maximum static friction between the boy and the ground is 340 N.

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3 years ago

A storage tank containing oil (SG=0.92) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of o

blagie [28]

Answer:

a-1 Graph is attached. The relation is linear.

a-2 The corresponding height for 68 kPa Pressure is 7.54 m

a-3 The corresponding weight for 68 kPa Pressure is 1394726kg

b The original height of the column is 5.98 m

Explanation:

Part a

a-1

The graph is attached with the solution. The relation is linear as indicated by the line.

a-2

By the equation

$P=\rho \times g \times h$

Here

P is the pressure which is given as 68 kPa.
ρ is the density of the oil whose SG is 0.92. It is calculated as

$\rho=S.G \times \rho_{water}\\\rho=0.92 \times 1000 kg/m^3\\\rho=920 kg/m^3\\$

g is the gravitational constant whose value is 9.8 m/s^2
h is the height which is to be calculated

$P=\rho \times g \times h\\h=\frac{P}{\rho \times g}\\h=\frac{68 \times 10^3}{920 \times 9.8}\\h=7.54m$

So the height of column is 7.54m

a-3

By the relation of volume and density

$M=\rho \times V$

Here

ρ is the density of the oil which is 920 kg/m^3
V is the volume of cylinder with diameter 16m calculated as follows

$V=\pi r^2h\\V=3.14\times (8)^2 \times 7.54\\V=1515.23 m^3$

Mass is given as

$M=\rho \times V\\M=920 \times 1515.23\\M=1394726kg$

So the mass of oil leading to 68kPa is 1394726kg

Part b

Pressure variation is given as

$\Delta P=P_{obs}-P_{atm}\\\Delta P=115-101 kPa\\\Delta P=14 kPa\\$

Now corrected pressure is as

$P_c=P_g-\Delta P\\P_c=68-14 kPa\\P_c=54 kPa$

Finding the value of height for this corrected pressure as

$P_c=\rho \times g \times h\\h=\frac{P_c}{\rho \times g}\\h=\frac{54 \times 10^3}{920 \times 9.8}\\h=5.98m$

The original height of column is 5.98m

4 0

4 years ago

How does a metamorphic rock become an igneous rock?

Oksana_A [137]

Answer:

If the newly formed metamorphic rock continues to heat, it can eventually melt and become molten (magma). When the molten rock cools it forms an igneous rock. Metamorphic rocks can form from either sedimentary or igneous rocks.

7 0

3 years ago

how is the acceleration of a car traveling on an elevated air track related to the angle of elevation

quester [9]

Acceleration is a vector quantity that expresses the rate of change in velocity. Being a vector quantity, then the value has magnitude and direction. If the car exerts a constant net force as it travels, the greater the angle of elevation is, the greater is the decrease in its acceleration. Since the vertical component of is affected by the acceleration due to the gravity, that is why vehicles exert more force to climb a steeper hills.

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3 years ago

The momentum of an object is determined to be 7.2 x 10-3 cm kg x m/s. Express this as provided or use any equivalent unit. How i

Leno4ka [110]

Complete Question:

The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g).

Answer:

7.2 gm/s.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

$Momentum = mass * velocity$

Given the following data;

Momentum = 7.2 * 10^-3 kgm/s

1 kg = 1000 g

Substituting the unit in kilograms with grams, we have;

Momentum = 7.2 * 10^-3 * 1000 gm/s

<em>Momentum = 7.2 gm/s. </em>

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3 years ago