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Nat2105 [25]
3 years ago
14

At the end of the movie Titanic, Rose lies on a piece of furniture, floating in the ocean, and Jack drowns. A common objection p

osed to this scene is that there’s room on the furniture for Jack as well, so why didn’t she let him get on it with her?
Let’s assume that the piece of furniture has an area of 1.5 m , a thickness of 5 cm, and is made of pine (ρ = 350 kg/m3). Assuming Rose has a mass of 46 kg and Jack has a mass of 58 kg, could they have both managed to stay afloat on the raft together? Assume the density of seawater is approximately 1025 kg/m3 and that the raft is completely submerged when rose is on top of it.
Physics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

If jack is in the piece of furniture it would submerge.

Explanation:

The piece of furniture would submerge if the  weight applied on the furniture is greater than the maximum buoancy force the water can provide.

maximum buoacy force = density of liquid × volume submerged× acceleration due to gravity.

                                       = 1025\times v\times 9.8

v = area × thickness of pine

  1.5\times 5\times 10^{-2}

 = 0.075 m^{3}

therefore buoancy force = 1025×0.075×9.8 N

                                         = 753.375 N

weight of rose alone = 46×9.8 N = 450.8 N

weight of jack alone = 58×9.8 = 568.4 N

weight of pine = density of pine × volume of pine

                        = 350 × 0.075= 26.25 N

weight of pine + weight of rose = 450.8+26.25=477.05 N

weight of pine + rose + jack = 477.05 + 568.4 = 1045.45 N

therefore if jack is in the piece of furniture it would submerge.

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Soccer fields vary in size. a large soccer field is 115 m long and 85 m wide. what are its dimensions in feet and inches? (assum
Irina18 [472]

The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.

The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.

As it is given that 1 m =3.281 ft

Therefore the length of the soccer field in ft is

115*3.281=377.315 ft

And width of the field is 85*3.281=277.885 ft

We know that 1 ft =12 in

Therefore the length of the soccer field in in is

377.315*12=4527.78 in

And width of the field is 277.885 *12=3334.62 in

8 0
3 years ago
Calculate the density of a solid of mass 20kg if it occupies a volume of 4m³​
choli [55]

Answer:

Density=Mass/Volume

            =20/4 kg/m^3

            =5 kg/m^3

4 0
3 years ago
Suppose you walk 11 m in a direction exactly 24° south of west then you walk 21 m in a direction exactly 39° west of north. 1) H
DENIUS [597]

Answer:

(1) 42.94 m

(2) 16.02^\circ

Explanation:

Let us first draw a figure, for the given question as below:

In the figure, we assume that the person starts walking from point A to travel 11 m exactly 24^\circ south of west to point B and from there, it walks 21 m exactly 39^\circ west of north to reach point C.

Let us first write the two displacements in the vector form:

\vec{AB} = (-11\cos 24^\circ\ \hat{i}-11\sin 24^\circ\ \hat{j})\ m =(-10.05\ \hat{i}-4.47\ \hat{j})\ m\\\vec{BC} = (-21\sin 39^\circ\ \hat{i}+21\cos 39^\circ\ \hat{j})\ m =(-31.22\ \hat{i}+16.32\ \hat{j})\ m

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

\vec{AC}=\vec{AB}+\vec{BC}\\\Rightarrow \vec{AC}=(-10.05\ \hat{i}-4.47\ \hat{j})\ m+(-31.22\ \hat{i}+16.32\ \hat{j})\ m\\\Rightarrow \vec{AC}=(-41.25\ \hat{i}+11.85\ \hat{j})\ m

Part (1):

the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

AC=\sqrt{(-41.25)^2+(11.85)^2}\ m= 42.94\ m

Part (2):

As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.

The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

\theta = \tan^{-1}(\dfrac{11.85}{41.27})\\\Rightarrow \theta = 16.02^\circ

4 0
3 years ago
Hellppppp&/&/&/&//&/&/&/&/&& will give brainiest
Komok [63]

Explanation:

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im soo so sorry

3 0
3 years ago
A man stands on roof of a house and drops a ball of mass M (from rest) from a height of 10 m above the ground. Its speed just be
horsena [70]

Answer:

Vf = 14 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics, which is independent of the mass of the object.

v_{f} ^{2} =v_{o} ^{2} +(2*g*x)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

x = distance = 10 [m]

Now replacing:

Vf² = 0 + (2*9.81*10)

Vf = 14 [m/s]

4 0
3 years ago
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