The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.
The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.
As it is given that 1 m =3.281 ft
Therefore the length of the soccer field in ft is
115*3.281=377.315 ft
And width of the field is 85*3.281=277.885 ft
We know that 1 ft =12 in
Therefore the length of the soccer field in in is
377.315*12=4527.78 in
And width of the field is 277.885 *12=3334.62 in
Answer:
(1) 42.94 m
(2) 
Explanation:
Let us first draw a figure, for the given question as below:
In the figure, we assume that the person starts walking from point A to travel 11 m exactly
south of west to point B and from there, it walks 21 m exactly
west of north to reach point C.
Let us first write the two displacements in the vector form:

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

Part (1):
the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

Part (2):
As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.
The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

Explanation:
i really didn't understand the question
im soo so sorry
Answer:
Vf = 14 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics, which is independent of the mass of the object.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
x = distance = 10 [m]
Now replacing:
Vf² = 0 + (2*9.81*10)
Vf = 14 [m/s]