When an atom of Calcium (Ca) bonds with an atom of Oxygen (O), the Calcium atom will have which ionic charge?

You come home and find that there's been a power outage while food was cooking in the slow cooker. What should you do wit the fo

klasskru [66]

Answer:

Well you can not serve it because it is a slow cooker it cooks slow and the refrigerator uses power.Stove tops use power too, I wouldn't feed it to the dog because it whatever you made could possibly make the dog sick and throwing it away is a waste of money. Out of all of those explanations choose the best one. Which ever one you pick whether right or wrong, think about it.

Explanation:

7 0

3 years ago

URGENT CHEMISTRY EXPERT!

vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

$\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl$

(b) Moles of CuCl₂

$\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} = \text{3.340 mmol CuCl}_{2}$

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

$\text{Moles of Na$_{3}$PO}_{4} = \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}$

(d) Volume of Na₃PO₄

$V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}$

Part 2. Net ionic equation

(a) Molecular equation

$\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})$

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

7 0

3 years ago

Consider a transition of the electron in the hydrogen atom from n=5 to n=9. Determine the wavelength of light that is associated

lesantik [10]

Lol i need to answer more and plus n could also = # 4.65

5 0

4 years ago

How many moles of glucose are in 19.1g of glucose?

Crank

Answer:

0.106 mol (3s.f.)

Explanation:

To find the number of moles, divide the mass of glucose (in grams) by its Mr. Glucose has a chemical formula of C6H12O6. To find the Mr, add all the Ar of all the atoms in C6H12O6.

Ar of C= 12, Ar of H= 1, Mr of O= 16

These Ar values can be found on the periodic table.

Mr of glucose= 6(12)+ 12(1) + 6(16)= 180

Moles of glucose

= mass ÷ mr

= 19.1 ÷ 180

= 0.106 mol (3 s.f.)

3 0

3 years ago

A researcher dilutes 30.0 ml of ethanol to 300.0 ml with distilled water. what is the percentage concentration by volume of the

Len [333]

Answer: 9.09 %

Explanation:

To calculate the percentage concentration by volume, we use the formula:

$\text{Volume percent of solution}=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

Volume of ethanol (solute) = 30 ml

Volume of water (solvent) = 300 ml

Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml

Putting values in above equation, we get:

$\text{Volume percent of solution}=\frac{30}{30+300}\times 100=9.09\%$

Hence, the volume percent of solution will be 9.09 %.

3 0

3 years ago

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