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aalyn [17]
3 years ago
15

Fear me or i am glory i give you free p oints \ / _| |_

Physics
2 answers:
svp [43]3 years ago
6 0

Answer:

AAAAAAAAAAH

Explanation:

scary '='

8_murik_8 [283]3 years ago
3 0

Answer:

kayyy

Explanation:

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Hello, my younger sister is stuck on this and I just got on here to ask this question. I have my original account but I just mad
nignag [31]

Answer:

Hi there!

I'm sorry your sister is struggling!

I am an edgenuity student in grade 11, I could probably help!

A trend is a line on a graph that all points seem to follow. This is best explained when thinking about line of best fit. If all your points go upward each time and are closed together, we can find the line that gets closest to each point!

Think of a trend as a pattern. The line of best fit, created by analyzing the trends, helps us guess at what the data points beyond what we have will equal

Is there any clarification she needs?

4 0
3 years ago
What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25
Rom4ik [11]

Acceleration of the ball is 50 m/s^2

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg. After the two
IrinaVladis [17]

This question involves the concepts of the law of conservation of momentum.

The magnitude of the final momentum of the eight ball is "0.22 N.s".

According to the law of conservation of momentum:

P_{i1}+P_{i2}=P_{f1}+P_{f2}

where,

P_{i1} = initial momentum of the cue ball = 0.23 N.s

P_{i2} = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)

P_{f1} = final momentum of the cue ball = 0.01 N.s

P_{f2} = final momentum of the eight ball = ?

Therefore,

0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

3 0
3 years ago
A stunt driver drives a car horizontally off the edge of a cliff at 3.8m/s and reaches the water below 2.5s later.
andreyandreev [35.5K]
A. The cliff was 30.7 m high
B. I also got 9.5 as the horizontal distance

Here is my work, I find making charts like this one to find knowns and unknowns can be helpful

4 0
3 years ago
A child of mass m is standing at the edge of a carousel. Both the carousel and the child are initially stationary. The carousel
suter [353]

Answer:

the angular velocity of the carousel after the child has started running =

\frac{2F}{mR} \delta t

Explanation:

Given that

the mass of the child = m

The radius of the disc = R

moment of inertia I = \frac{1}{2} mR^2

change in time = \delta \ t

By using the torque around the inertia ; we have:

T = I×∝

where

R×F = I × ∝

R×F = \frac{1}{2} mR^2∝

F = \frac{1}{2} mR∝

∝ = \frac{2F}{mR}           ( expression for angular  angular acceleration)

The first equation of motion of rotating wheel can be expressed as :

\omega = \omega_0  + \alpha  \delta t

where ;

∝ = \frac{2F}{mR}    

Then;

\omega = 0+ \frac{2F}{mR} \delta t

\omega =  \frac{2F}{mR} \delta t

 

∴ the angular velocity of the carousel after the child has started running =

\frac{2F}{mR} \delta t

7 0
3 years ago
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