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meriva
3 years ago
6

a parking lot is going to be 60m wide and 240m long which dimensions could be used please please help

Physics
2 answers:
Wewaii [24]3 years ago
4 0

Answer:

A = 20x80

Explanation: DID IT ON APEX

Bezzdna [24]3 years ago
3 0

Answer: The area of the parking lot is 14,400 meters squared.

Explanation:

We have the dimensions of the parking lot.

60m by 240m

The units used here are meters.

Now, if we want to know the area of the parking lot is equal to the product between the length and the width:

A = 60m*240m = 14,400 m^2

The area of the parking lot is 14,400 meters squared.

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An electric field of 260 000 n/c points due west at a certain spot. what are the magnitude and direction of the force that acts
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the force on the charge is 1820000 N and is directed along the west.

Explanation:

Force = F =q E

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E= electric field=260000 N/C

so F=7 (260000)

F=1820000 N

The force acting on the charge is along west.

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A wave x meters long has a speed of y meters per second. The frequency of the wave is
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The answer is B. y/x hertz.

Frequency of a wave is defined as the ratio between the speed and wavelength of the wave. The unit of frequency is hertz (Hz) which is also equivalent to s^-1 or "per second". Following the units of wavelength (m) and speed (m/s), it can also be inferred that frequency is equal to (m/s)/m or y/x.
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A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring with a spring constant of 2
Tom [10]

the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:

  • The range of motion is: A = 4.44 cm

<h3>Oscillatory movement.</h3>

The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.

            x = A cos (wt + Ф)

            w² = k/m

where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.

Let's find the angular velocity/

            w= \sqrt{ \frac{200}{0.300} }

            w = 25.8 rad/s

Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:

             v= \frac{dx}{dt}

             v= - A w sin (wt +Ф)

             

             0 = -A w sin Ф

            Ф= 0

They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time

Position.

               4.00 = A cos 25.8t

Speed.

              50.0 = - At 25.8 sin 25.8t

To solve the system, ;et's square and add.

              Cos² 25.8t = \frac{16}{A^2}

              sin² 25.8t = \frac{3.756}{A^2 }

              1 = \frac{1}{A^2} \ (16 + 3.756)

               A = \sqrt{19.756}

               A= 4.44 cm

In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:

The range of motion is: A = 444 cm

Learn more about oscillatory motion here:  brainly.com/question/14311816

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2 years ago
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to make sure the argument is true and correct backed up by logic.

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