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Pavlova-9 [17]
3 years ago
14

Include units with all of your answers. A 1.84 kg bucket full of water is attached to a 0.76 m long string.

Physics
1 answer:
aleksandrvk [35]3 years ago
7 0
<span>c. What is the magnitude of the tension in the string at the bottom of the circle if you are swinging it at 3.37 m/s? </span>
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A very humble bumble bee is flying horizontally due North at a constant speed of 3.11 m/s. At the current location of the bumble
Reil [10]

To solve this problem we will apply the concepts of the Magnetic Force. This expression will be expressed in both the vector and the scalar ways. Through this second we can directly use the presented values and replace them to obtain the value of the magnitude. Mathematically this can be described as,

\vec{F_B} = q(\vec{V}\times \vec{B})

F_B = q|v||B| sin\theta

Here,

q = Charge

v = Velocity

B = Magnetic field

\theta = \text{Angle between } \vec{B} \text{ and } \vec{V}

Our values are given as,

\theta = 35.7\°

q = 22.5*10^{-9}C

B = 1.05*10^{-5}T

v = 3.11m/s

Replacing,

F_B = (22.5*10^{-9}C)(3.11 \times 1.05*10^{-5}) sin(35.1\°)

F_B = 4.224*10^{-13}N

Therefore the size of the magnetic force acting on the bumble bee is 4.22*10^{-13}N

3 0
3 years ago
A rifle has a mass of 7-kg and the bullet has a mass of 0.7-kg. If the velocity of the bullet is 350-m/s after the rifle is fire
nevsk [136]

Answer:

-35 m/s

Explanation:

Momentum is conserved.

Momentum before firing = momentum after firing

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Before the bullet is fired, the bullet and rifle have no velocity, so u₁ and u₂ are 0.

0 = m₁v₁ + m₂v₂

Given m₁ = 0.7 kg, v₁ = 350 m/s, and m₂ = 7 kg:

0 = (0.7 kg) (350 m/s) + (7 kg) v

v = -35 m/s

The rifle recoils at 35 m/s in the opposite direction.

8 0
3 years ago
The electric field of a sinusoidal electromagnetic wave obeys the equation E = (360V/m) sin[ (6.00×1015rad/s)t + (1.96×107rad/m)
malfutka [58]

Answer:

Option D is correct.

Explanation:

Bmax = Emax / c

The general form for electromagnetic wave equation is

E = jEmax ×cos(kx-wt)

We were given

(360V/m) sin[ (6.00×1015rad/s)t + (1.96×107rad/m)x ].

So from the equation above

Emax = 360V/m

Bmax = 360/(3×10⁸) = 1.2 ×10‐⁶ T.

5 0
3 years ago
Read 2 more answers
Your car is stalled in the middle of a large patch of ice (assumed to be frictionless). You have a friend that has thrown a rope
Gnoma [55]

Answer:

The time depends on the distance that they have to travel

x(t) = \frac{0.3846t^{2} }{2}

Explanation:

The only horizontal force exerts over the car and you, it is the force that your friend is applied

Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus

\sum{F} = ma

        550 = 1430a

            a = 0.3846 m/s2

             

The car and you have a motion under constant acceleration, then theirs position to a time-based is:

x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}

By the initial conditions

x(t) = \frac{at^{2} }{2}

x(t) = \frac{0.3846t^{2} }{2}

The time depends on the distance that they have to travel  

7 0
4 years ago
How would playing a game of soccer, baseball, or basketball be different if inertia didn’t exist?
Elina [12.6K]
This would be a funny game.

Inertia, according to first Law of Newton, means that when you throw a ball it will continue moving unless a force acts over it.

Without inertia, the ball instead of continue moving, would stop as soon as it leaves your hand or foot. You had to stay pasted to the ball unitl it reaches the desired destiny for it continue moving. 
5 0
3 years ago
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