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Softa [21]
3 years ago
12

Earth has one moon and mars has two moons. how many more moons are found around the outer planets than the inner planets?

Chemistry
2 answers:
Travka [436]3 years ago
7 0
The outer planets are <span>Jupiter, Saturn, Uranus and Neptune while the inner planets are Mercury, Venus, Earth, and  Mars. The outer planets have more moons than the inner planets because these planets are much larger than the inner ones. The inner planets are terrestrial while larger ones are called gas giants, mostly made up of gas.</span>
Fudgin [204]3 years ago
5 0

Answer:

There are 8 planets in the solar system. 4 inner planets are Mercury, Venus, Earth and Mars.

Mercury and Venus don't have any moons. Earth has one moon. Mars has two moons.

The 4 outer planets are: Jupiter, Saturn, Uranus and Neptune.

Jupiter has 67 moons, Saturn has 62 moons, Uranus has 27 and Neptune has 14 moons.

The outer planets have about 167 more moons than inner planets. Thus, outer planets have many more moons than inner planets.

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If the outside of your flask is not dry when the first mass determination is made and it is dried for the second mass determinat
svlad2 [7]

Answer:

You'll experience a grater deviation

Explanation:

<em>You'll experience a greater deviation in your measurements, meaning your measures will have a bigger difference between them, and the greater these deviations the less accurate will be the measuring.</em> This happens mainly because you're not replicating the measurement with the exact same conditions, in one of them you'll have an extra mass from the water.

I hope you find this information useful and interesting! Good luck!

8 0
3 years ago
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

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3 years ago
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To the top. Common knowledge my dude. Heat always rises to the top.
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The answer is 20 I think
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