Answer:C) Sticking the balloon in a freezer.
Explanation:
Sticking the balloon in a freezer will cause the pressure to drop because the air inside will become colder and lead to the particles having lower kinetic energies. In, turn their rate of collisions will decrease and cause the pressure to drop. Leaving the balloon in a hot car and squeezing the balloon will cause a pressure increase and taking the balloon to the top of a hill may or may not cause a pressure increase.
W = weight of the body in air = 160 N
ρ' = density of body
V = volume of the body
weight of the body in air is given as
W = ρ' V g eq-1
W' = weight of the body in liquid = 120 N
force of buoyancy is given as
F = W - W'
F = 160 - 120
F = 40 N
ρ = density of liquid = ?
force of buoyancy is given as
F = ρ V g eq-2
dividing eq-1 by eq-2
160/40 = ρ' V g /(ρ V g )
4 = ρ' /(0.8 )
ρ' = 3.2
(b)3.2
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
- L = 2.5 m
- y = .0125
- λ = 600 nm
As we know, the equation
⇒
On substituting the values, we get
⇒
On applying cross multiplication, we get
⇒
⇒
⇒
For new distance, we have to put this value of "a" in the above equation,
⇒
⇒
⇒
⇒
The total distance will be twice the value of "y", we get
=
or,
=