Explanation:
The net force of each square is the combination of the forces in each direction. The direction is the... direction the square would go in due to the net force. The magnitude of the net force is how large it is. So if you had a force pushing 2N to the left and 1N to the right, then the net force would be 1N to the left; because the two oppose eachother. If they were going in the same direction, then they'd add to each other. And perpendicular net forces (like one pushing up and another pushing left) can create net forces in diagonal directions.
I'm not going to do all of these for you because they're basically all the same thing and it's good practice for you anyway. But I'll do the first three just so you can get the idea:
1. The net force's magnitude is 4N and it's direction is to the right.
2. The net force's magnitude is 4N and it's direction is to the left.
3. The net force's magnitude is 0N and it has no direction because they are equal forces acting in opposite directions.
Answer: 0.078
Explanation:
Given variables:
R1 = 25.0 , R2 = 64.0 , I1 = 0.200
Step 1: find V
0.200 = v/25
0.200 * 25 = v
5 = v
Step 2: Solve for I2
I = V/R
I = 5/64
I = 0.078125
Hope this helps!
The right answer for the question that is being asked and shown above is that: "The angle of refraction of the light ray as it enters the transparent block from air = 20 degrees." A ray of monochromatic light (f=5.09x10^14 hz) passes through air and a rectangular transparent block calculate the absolute index of refraction for the <span>medium of the transparent block </span>
Answer:
there will be collision
Explanation:
= speed of sue = 34 m/s
= speed of van = 5.20 m/s
= speed of sue relative to van =
= 34 - 5.20 = 28.8 m/s
= stopping distance after brakes are applied
= distance between sue and van = 160 m
= final speed of sue = 0 m/s
= acceleration = - 1.80 m/s²
Using the kinematics equation


m
Since
hence there will be collision
Answer:
The average force that brings the car to rest is 175000N
Explanation:
The mass of the car, m = 1000 kg
Initial speed, u = 14 m/s
Final speed, v = 0 m/s (Since the car comes to a stop)
The time taken, t = 8 x 10^-2 s
The average force is calculated as:

The average force that brings the car to rest is 175000N