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Natali [406]
2 years ago
9

Write short notes on:human made wetland​

Physics
1 answer:
kogti [31]2 years ago
4 0

Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.

<h3>What is a human-made wetland​ ?</h3>

Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.

In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.

In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.

The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.

Hence, the human-made wetland​ is an artificial wetland.

To learn more about the human-made wetland​ refer;

brainly.com/question/1334452

#SPJ1

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Select the correct answer.
kvasek [131]

Answer:

8.37×10⁻⁴ N/C

Explanation:

Electric Field: This is the ratio of electrostatic force to electric charge. The S.I unit of electric field is N/C.

From the question, the expression for electric field is given as,

E = F/Q.......................... Equation 1

Where E = Electric Field, F = force experienced by the charged balloon, Q = Charge on the balloon.

Given: F = 8.2×10⁻² Newton, Q = 9.8×10 Coulombs = 98 Coulombs

Substitute these values into equation 1

E = 8.2×10⁻² /98

E = 8.37×10⁻⁴ N/C

Hence the Electric Field of the charged balloon =  8.37×10⁻⁴ N/C

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3 years ago
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If a hockey stick exerts a force of 40 N on a 0.5-kg puck, what will the
antoniya [11.8K]

Answer:

  B.  80 m/s²

Explanation:

F = ma

a = F/m = (40 N)/(0.5 kg) = 80 m/s²

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3 years ago
Which is a gas at room temperature?
Sedaia [141]
<span>Which is a gas at room temperature?
</span>B) nitrogen

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3 years ago
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What equation explains the relation between amperes, watts and volts?
I am Lyosha [343]
I think Option B, i’m sorry if that’s wrong.
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A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
kykrilka [37]

Explanation:

It is given that,

Mas of the car, m_1=1170\ kg

Initial speed of the car, u_1=25\ m/s

Mass of the truck, m_2=9800\ kg

Initial speed of the car, u_2=20\ m/s

Final speed of the car, v_1=18\ m/s

(a) It is a case of elastic collision. Let v_2 is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{1170\times 25+9800\times 20-1170\times 18}{9800}

v_2=20.83\ m/s

(b) Initial kinetic energy is given by :

k_i=\dfrac{1}{2}(m_1u_1^2+m_2u_2^2)

k_i=\dfrac{1}{2}\times (1170\times (25)^2+9800\times (20)^2)

k_i=2325625\ J

Final kinetic energy is given by :

k_f=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

k_f=\dfrac{1}{2}\times (1170\times (18)^2+9800\times (20.83)^2)

k_f=2315595.61\ J

The change in mechanical energy of the car truck system in the collision:

\Delta K=k_f-k_i

\Delta K=2315595.61-2325625

\Delta k=-10029.39\ J

The loss in kinetic energy is 10029.39 Joules.

(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.

Hence, this is the required solution.

6 0
3 years ago
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