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3 years ago

What is th current hypothesis on how the earths moon was formed?

2 answers:

8 0

The hypothesis is that around four and a half billion years ago, a mars-sized planetary object collided with the forming earth, merging the two masses at the expense of a massive amount of ejecta. This particulate ejecta, influenced by the local gravity, attracted together and formed the moon, locked tidally to the earth.

TEA [102]3 years ago

7 0

Answer:

The current accepted theory is known as the Giant Impact Hypothesis, where according to this NASA webpage "Origin of the Earth and Moon" (Taylor) a Mars sized object collided into the early Earth.

The prevailing theory supported by the scientific community, the giant impact hypothesis suggests that the moon formed when an object smashed into early Earth. Like the other planets, Earth formed from the leftover cloud of dust and gas orbiting the young sun.

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1 If you measured the distance travelled by a snail in

Fittoniya [83]

The answer is m/s hope it helps

3 0

2 years ago

A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d

cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

$\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg$

$Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}$

(b) By substituting the values

$Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}$

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0

3 years ago

By method of dimension show that the following equation are homogenous.

il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

Given equation is:

$H = \frac{u^2Sin^2\phi}{2g}$

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

$[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]$

Hence, the equation is proven to be homogenous.

ii)

$F = \frac{Gm_1m_2}{r^2}\\\\$

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

$[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\$

Hence, the equation is proven to be homogenous.

8 0

3 years ago

A force that keeps an object at a fixed angle

Helga [31]

I'm pretty sure it's called, "gravity". or gravy :)

3 0

3 years ago

A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers requi

puteri [66]

Answer:

$Rate = 1.71 burger/min$

Explanation:

Length of the conveyor belt is given as

$L = 1.2 m$

time taken to cook one burger is given as

$t = 2.8 min = 168 s$

now we can find the speed of the belt as

$v = \frac{distance}{speed}$

$v = \frac{1.2}{168}$

$v = 7.14 \times 10^{-3} m/s$

Now we know that the distance between two burgers is given as 25 cm

$d = 0.25 m/burger$

now the production rate of burgers is given as

$Rate = \frac{v}{d}$

$Rate = \frac{7.14 \times 10^{-3} m/s}{0.25 m/burger}$

$Rate = 0.0286\frac{burger}{sec}$

$Rate = 0.0286\times 60\frac{burger}{min}$

$Rate = 1.71 burger/min$

8 0

3 years ago