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3 years ago

4. The place on a magnet where the magnet exerts the strongest magnetic force

Physics

1 answer:

matrenka [14]3 years ago

3 0

The answer is b. force

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Susan

maxonik [38]

D. Was a leader in the woman's suffrage movement

7 0

2 years ago

What is carbon dating

Tom [10]

the determination of the age or date of organic matter from the relative proportions of the carbon isotopes carbon-12 and carbon-14 that it contains. The ratio between them changes as radioactive carbon-14 decays and is not replaced by exchange with the atmosphere.

7 0

3 years ago

Rearrange the kinetic energy equation so that velocity is the subject

mars1129 [50]

Answer: V = sqrt(2K.E/M)

Explanation:

K.E = 1 /2MV^2

MV^2 = 2 K.E

V^2 = 2K.E /M

V = sqrt(2K.E/M)

6 0

2 years ago

a tiger moving with constant accleration covers the distance between two points 70 meter apart in 7 seconds . its speed as it pa

makvit [3.9K]

Answer:

a = 1.428 [m/s²]

v₀ = 5 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

$x=x_{o}+v_{o}*t+\frac{1}{2}*a*t^{2}$

where:

x = final point [m]

x₀ = initial point [m]

v₀ = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

But we need to use this additional equation.

$v_{f}=v_{o}+a*t$

where:

vf = final velocity = 15 [m/s]

Now we can use this equation, replacing it, in the first one. We must bear in mind that the difference among x - x₀ is equal to 70 [m]

$x-x_{o}=v_{o}*t+\frac{1}{2}*a*t^{2} \\x-x_{o}=(v_{f}-a*t)*t+\frac{1}{2} *a*t^{2}\\70=(15-a*t)*t+\frac{1}{2}*a*t^{2}\\70=15*t-a*t^{2} +\frac{1}{2}*a*t^{2} \\70=15*t-\frac{1}{2}*a*t^{2}\\70=15*(7)-\frac{1}{2} *a*(7)^{2}\\105-70=0.5*a*49\\35=24.5*a\\a=1.428[m/s^{2} ]$

Now replacing this value in the second equation, we can find the initial velocity.

$15=v_{o}+1.428*7\\v_{o}=5[m/s]$

3 0

3 years ago

A student conducts an experiment in which an object travels across a horizontal surface while for 2 s a net force is applied to

erma4kov [3.2K]

Answer:

D. No, because the student needs to know the direction that the force is applied

Explanation:

The change in momentum depends on the direction of the force as well as its magnitude. Since the graph only supplies force magnitude information, it is insufficient to allow the student to calculate the change in momentum.

3 0

2 years ago