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Oksi-84 [34.3K]
3 years ago
12

Lydia is 9kg underweight. Caroline has an ideal weight for her height. Viv is 8kg overweight. Who is most likely to have the hig

hest blood pressure?
Physics
2 answers:
Crank3 years ago
5 0

Answer: Viv

Explanation:

UkoKoshka [18]3 years ago
4 0
Viv most likely —————-
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OverLord2011 [107]

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A. °C

Explanation:

{ \sf{degree \: celcius}}

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For the third one on the top you can put to get solar panels on your roof
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Two satellites orbit the Earth in circular orbits of the same radius. One satellite is twice as massive as the other. Which stat
loris [4]

To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.

This concept is expressed in the equation,

v = \sqrt{\frac{Gm_E}{r}}

Where,

G = Universal Gravitational constant

m_E = Mass of the Earth

Therefore the ratio of the velocity from two satellites is,

\frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}}

The ratio between the two satellites is the same, then

\frac{v_1}{v_2} = \sqrt{\frac{r}{r}}

\frac{v_1}{v_2} = 1

v_1 =v_2

Therefore the correct option is B.

4 0
3 years ago
bothersome feature of many physical measurements is the presence of a background signal (commonly called "noise"). In Part 2.2.4
serious [3.7K]

Answer:

Incomplete question: "A signal of 20.7 mV is measured at a distance of 29 mm and 15.8 mV is measured at 32.5 mm. Correct the data for background and normalize the data to the maximum value. What is the normalized corrected value at 32.5 mm?"

The normalized corrected value at 32.5 mm is 0.1638

Explanation:

The corrected light measurement at 29 mm is equal to:

20.7 - 5.1 = 15.6 mV

The corrected light measurement at 32.5 mm is equal to:

15.6 - 5.1 = 10.5 mV

To normalize the data to its maximum value means that the maximum value must be calculated and the data must be scaled using that value, as in this case the maximum value is 15.6 mm, then the normalized corrected value at 32.5 mm is equal to:

10.5 * 15.6 = 163.8 = 0.1638

6 0
3 years ago
A conductor shaped as a circular loop with a radius of 4.0 m is located in a uniform but changing magnetic field. If the maximum
bekas [8.4K]

Answer:

\frac{\delta B}{\delta t}= 0.0995 \  T/s

Explanation:

Given that :

The radius of the circular loop = 4.0 m

Maximum Emf E_{max} = 5.0 V

The  maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;

E_{max} = Area (A) * \frac{\delta B}{\delta t}

E_{max} = \pi r^2 * \frac{\delta B}{\delta t}

5.0 = \pi * (4.0)^2 * \frac{\delta B}{\delta t}

5.0 = 50.27 * \frac{\delta B}{\delta t}

\frac{\delta B}{\delta t}= \frac{5}{50.27}

\frac{\delta B}{\delta t}= 0.0995 \  T/s

5 0
3 years ago
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