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Oksi-84 [34.3K]
2 years ago
12

Lydia is 9kg underweight. Caroline has an ideal weight for her height. Viv is 8kg overweight. Who is most likely to have the hig

hest blood pressure?
Physics
2 answers:
Crank2 years ago
5 0

Answer: Viv

Explanation:

UkoKoshka [18]2 years ago
4 0
Viv most likely —————-
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If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is pr
Alinara [238K]

Answer:

Passed into the power grid for others to use the electricity

Explanation:

If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is produced is usually passed into the power grid for others to use the electricity, generating a income to the homeowner

4 0
3 years ago
The driver accelerates a 330.0 kg snowmobile, which results in a force being exerted that speeds up the snowmobile from 6.00 m/s
just olya [345]

Answer:

(a) 5610 kgm/s

(b) 5610 Ns.

(c)  78. 64 N

Explanation:

a. Change in momentum: This can be defined as the product of the mass of a body to its change in velocity. The S.I unit of change in momentum is kgm/s.

Mathematically, change in momentum is expressed as

ΔM = mΔv......................... Equation 1

Where ΔM = change in momentum, m = mass of snowmobile, Δv = change in velocity.

Given: m = 330 kg, Δv = v₂-v₁ = 23-6 = 17 m/s.

Note: v₁ and v₂ are the initial and the final velocity of the snowmobile.

ΔM = 330(17)

ΔM = 5610 kgm/s.

(b) Impulse: This can be defined as the product and force and time. The S.I unit of impulse is Ns.

Note: From Newton's second law of motion, impulse is equal to change in momentum.

Therefore,

I = ΔM................ Equation 2

Where I = impulse of the force.

Since ΔM = 5610 kgm/s.

Therefore

I = 5610 Ns.

Thus the impulse = 5610 Ns.

(c) Force: This can be defined as the product of the mass of a body and its acceleration. The S.I unit of force is Newton (N).

F = ma ................................. Equation 3

F = force, m = mass of the body, a = acceleration

But,

a = ( v₂-v₁)/t

Where v₂ = 23.0 m/s, v₁ = 6.0 m/s t = 60.0 s.

a = (23-6)/60

a = 0.283 m/s².

Substituting the value a and m into equation 3

F = 330(0.2383)

F = 78.639 N.

F ≈ 78. 64 N

8 0
3 years ago
The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the
Bad White [126]

Answer: c)• 2/3

Explanation:

Lets say q1 and q2 are two charges with r distance far apart.

So electrostatic force

F = (k q1 q2) / r²

as k = Coulomb's constant

Now

q1' = 2q1

q2' = q2/3

Therefore the new electrostatic force

F' = (k q'1 q'2) / r²

F' = (k 2q1 q2) / 3r²

F' = 2/3 [(k q1 q2) / r²]

so F' = 2/3F

New electrostatic force  is 2/3F

3 0
3 years ago
Liang is working with an electrical circuit. She replaces a straight electrical wire with a coiled wire. What is Liang most like
Romashka-Z-Leto [24]

increase the strength of the magnetic field when current flows through the circuit

She can change the arrows so they show current traveling in opposite directions on the sides of the loop.

halfway between the like poles of two magnets, because the field lines bend away and do not enter this area

A generator converts kinetic energy to electrical energy, and a motor converts electrical energy to kinetic energy.

A switch is closed, so the circuit would be complete and unbroken and the lights in the circuit would shine.

3 0
3 years ago
Read 2 more answers
A landing craft with mass 1.21×104 kg is in a circular orbit a distance 5.90×105 m above the surface of a planet. The period of
creativ13 [48]

Answer:

  W = 661.6 N

Explanation:

The weight of a body is the force of attraction of the plant on the body, so we must use the law of gravitational attraction

       F = G m M / r²

Where G is the gravitational attraction constant that values ​​6.67 10-11 N m² / kg², M is the mass of the planet and r is the distance from the center of the planet.

Let's look for the mass of the planet, for this we write Newton's second law for the landing craft

     F = m a

Acceleration is centripetal a = v² / r

     G m M / r² = m (v² / r)

The ship rotates rapidly (constant velocity module), let's use uniform kinematic relationships

    v = d / t

The distance of a circle is

    d = 2π r

    v = 2π r / t

We replace

     G m M / r² = m (4π² r² / t² r)

    G M = 4 π² r³ / t²

    M = 4π² r³ / G t²

The measured distance r from the center of the plant is

     r = R orbit + R planet

     r = 5.90 10⁵ + ½ 9.80 10⁶

     r = 5.49 10⁶ m

    M = 4 π² (5.49 10⁶)³ / (6.67 10⁻¹¹ (5.900 10³)²)

    M = 6,532 10²¹ / 2,321 10⁺³

    M = 2.814 10²⁴ kg

With this data we calculate the astronaut's weight

     W = (G M / R²) m

     W = (6.67 10⁻¹¹ 2,816 10²⁴ /(4.90 10⁶)2)   84.6

     W = 7.82  84.6

     W = 661.57 N

3 0
3 years ago
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