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antiseptic1488 [7]
3 years ago
15

If 17.8 g grams of lithium (Li) are combined with 50.0 grams of water (H20) there is

Chemistry
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

Explanation:

Li+H2O..................LiOH+H2

mass of Li=17.8 g

No of moles of Li=17.8/7=2.5

mass of H2O=50.0 g

No of moles of H2O=50.0/18=2.8

limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams

moles=given mass/molar mass

given mass=moles*molar mass

molar mass of LiOH=24

mass=2.5*24=60 gram

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A cylinder contains 250 g of Helium at 200 K. The external pressure is constant at 1 atm. The temperature of the system is raise
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Answer:

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Explanation:

<u>Step 1: </u>Data given

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8 0
3 years ago
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