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scoundrel [369]
3 years ago
15

How many milliliters of 0.121 M HCl are needed to neutralize 44.3 mL 0.274 M Ba(OH)2? Write the equation and don't forget to bal

ance it! Report your answer to the tenths place. Do not include units.
Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

100 mL is the volume of HCl needed to neutralize the 44.3 of Ba(OH)₂

Explanation:

This is the chemical equation:

2HCl + Ba(OH)₂  →  BaCl₂ + 2H₂O

Formula for neutralization is:

Molarity of acid . Volume of acid = Molarity of base . Volume of base

0.121 . Volume of acid = 0.274 . 44.3

Volume of acid = (0.274 . 44.3) / 0.121 → 100

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Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

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First of all we will write the balance chemical equation.

2C₆H₁₄O₂  +  17O₂  →   14CO₂  +  12H₂O

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moles of C₆H₁₄O₂ =  16.5 g × 118 g/mol

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Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

                 O₂      :     CO₂

                 17       :      14

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                    2    :      14

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Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

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