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avanturin [10]
3 years ago
8

Consider an acidic chromate-dichromate system at equilibrium in which the color is an orange-yellow. The reaction is represented

by the equation:Cr2O72-(aq) + H2O(l)↔ CrO42+(aq) + H+(aq) orange yellow Which of the following best describes what happens if a strong base is added to the system at equilibrium? Explain your answer.
Chemistry
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

The equilibrium will move in forward direction.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Cr_2O_7^{2-}(aq)+H_2O(l)\rightleftharpoons 2CrO_4^{+}(aq)+2H^+(aq)

On addition of base at the equilibrium, the hydroxide ions of the base will neutralize the hydrogen ions and lowering in concentration of hydrogen ion will be observed.

So, on lowering of concentration of hydrogen ions the equilibrium will move in direction in accordance to Le Chatelier’s Principle .The equilibrium will move in forward direction.

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Do metals donate or accept electrons? what do they become after they donate/accept electrons?
valentinak56 [21]
Metal usually donates electrons. The concept behind this phenomenon is stability. The elements with the most stable electronic configuration are the noble gases in Group 5A. As a result, the other elements donate or accept electrons so that they would be like the noble gases. Since metals are past their nearest noble gas element, they have to shed their electrons. When they do, they become cations which are positively charged ions.
8 0
4 years ago
A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution
tresset_1 [31]

Answer:

.125 M

Explanation:

.15 M/L   * .125 L = .01875 moles

now dilute to 150 cc  (by adding 25 cc)

.01875M / (150/1000) = .125M

5 0
2 years ago
Calcutale Grxn for the following equation at 25°C: <br><br> 4KClO3(s) → 3KClO4(s) KCl(s)
Step2247 [10]

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

5 0
3 years ago
I need you to solve for me plzzzzzz
Sergeu [11.5K]

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

<h3 />
3 0
3 years ago
On headedama be prepared​
mixer [17]

Answer:

yes

Explanation:

yea

3 0
3 years ago
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