Answer:
It's a individual form of life. Examples of this are bacterium , protists and fungus
Answer:
(a): It spends on the trip 2.75 hr (2 hours 45 minutes)
(b): The person travels 213.9 km.
Explanation:
Vp= 77.8 km/h
V1= 89.5 km/h
V2= 0 km/h
t2= 0.36hr
t1= ?
Vp= (V1*t1 + V2*t2) / (t1 + t2)
clearing t1:
t1= 2.39 hr
Trip time= t1+t2
Trip time= 2.75 hr (a)
Distance traveled= V1*t1
Distace traveled= 213.9 km (b)
Answer:
Volume of the sample: approximately 
.
Average density of the sample: approximately 
.
Assumption:
. 
.- Volume of the cord is negligible.
Explanation:
<h3>Total volume of the sample</h3>
The size of the buoyant force is equal to 
.
That's also equal to the weight (weight, 
) of water that the object displaces. To find the mass of water displaced from its weight, divide weight with 
.
.
Assume that the density of water is . To the volume of water displaced from its mass, divide mass with density 
.
.
Assume that the volume of the cord is negligible. Since the sample is fully-immersed in water, its volume should be the same as the volume of water it displaces.
.
<h3>Average Density of the sample</h3>
Average density is equal to mass over volume.
To find the mass of the sample from its weight, divide with .
.
The volume of the sample is found in the previous part.
Divide mass with volume to find the average density.
.
Answer: 22 batches.
Explanation:
Given that 11 kg is a familiar weight for a bag of flour. Also, it is given that It takes 500 g of flour to make one batch of cookies.
How many batches of cookies can you make with one bag of flour
Let's first convert 11 kg into grams (g) by multiplying it by 1000
11 × 1000 = 11000 g
Divide 11000 by 500
11000/500 = 22
Therefore, 22 batches of cookies can be made with one bag of flour.
We are given an electromagnetic wave with a frequency of 5.09 x 10^14 Hz and travelling through a transparent medium. If the medium was vacuum, the speed of the wave would be equal to the speed of light. Otherwise, the main factor that would determine the speed of the wave is its wavelength.
