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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Physics

1 answer:

Ede4ka [16]3 years ago

3 0

B is the correct answer because the more mass the person has the harder it will be for the opposing team to pull on the other team.

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Suppose we have a space ship orbiting the earth. What must happen in order for the spaceship to leave orbit and fall back toward

sdas [7]

Answer:

#2) The spaceship's forward motion must be slowed down so the earth's gravitational pull on it will be stronger than the ship's forward motion.

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1 year ago

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A particle with charge 5 . 0- µ C is placed at the corner of a cube. (Physics Help)? A particle with charge 5.0-µC is placed at

Svetradugi [14.3K]

Gauss law states that the electric flux through any closed surface is proportional to the net electric charge inside the surface. This is expressed mathematically in the form of:

Φ = Q / εo

Where,

Φ = the electric flux = unknown (which we have to find for)

Q = the net electric charge = 5.0 µC = 5 E-6 C

εo = the permittivity of free space = a constant value = 8.85 E-12 C^2 / N m^2

Plugging in the values into the equation will result in:

Φ = 5 E-6 C / (8.85 E-12 C^2 / N m^2)

Φ = 564,971.75 Wb = <span>5.6 x 10^5 Wb </span>

6 0

3 years ago

Can someone please help me ASAP

Serggg [28]

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

$t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]$

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

8 0

2 years ago

Seasons are a result of:

Ber [7]

Earths tilt on the axis.

7 0

3 years ago

A person hums in a well (closed) and finds strong consecutive resonance frequencies of 60 Hz, 100 Hz, and 140Hz...

I am Lyosha [343]

Answer:

fundamental frequency= 20Hz

length= 4.3m

Explanation:

resonating frequencies = 60 Hz,100 Hz,140 Hz

speed of sound =344 m/s

as well behaves as organ pipe with are end closed

only odd harmonics are allowed

, so the vibration will corresponds to n=1,3,5,7....

(2n−1) λ

/4 = l (∵λ

= V/f)

(2n-1) V / 4f = l

$\frac{(2m-1)344}{4*60} = \frac{(2n-1)344}{4*100} = \frac{(2p-1)344}{4*140}$

(2m-1)/6= (2n-1)/10= (2p-1)/14 =A

The given frequencies happen to be 3rd,5th & 7th harmonics of the fundamental frequency n=20Hz.

Therefore, The fundamental frequency will be 20 Hz because 60 Hz is corresponding 3rd harmonic

In order to find length,

(2n-1) V / 4f = l

$\frac{1*344}{4 20}$ = 4.3m

therefore, the well is 4.3m deep

8 0

2 years ago