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Nina [5.8K]
4 years ago
5

PLEASE HELP WILL GIVE BRAINLIEST

Physics
1 answer:
Ede4ka [16]4 years ago
3 0
B is the correct answer because the more mass the person has the harder it will be for the opposing team to pull on the other team.
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3 years ago
A current of 0.86 a flows through a copper wire 0.47 mm in diameter when it is connected to a potential difference of 15 v. how
likoan [24]

To calculate the length of the wire, we use formulas,

R = \frac{V}{I}                                       (A)

R= \rho  \frac{l}{A}                                (B)

Here, R is the resistance of the wire, I is the current flows through wire and V is potential difference. A is cross sectional area of wire and \rho is the density of copper wire and is value,\rho = 1.7\times 10^{-8} \Omega m.

Given    I = 0.86 A,V=15 V and  r = \frac{0.47 mm}{2} =2.35 \times 10^{-4} m, V= 15 V.

Substituting the values of I and V in equation (A ) we get,

R=\frac{15V}{0.86A} = 17.44 \Omega

Now from equation (B),

l=\frac{R A}{\rho }

Therefore,

l= \frac{17.44\times\pi \times r^2  }{1.7\times 10^{8} \Omega m} \\\\ l= \frac{17.44\times 3.14 \times(2.35\times10^{-4}m)^2  }{1.7\times 10^{-8} \Omega m} = 177.9 m

Thus the length of the copper wire is 177.9 m.

8 0
3 years ago
A 0.600-mm diameter wire stretches 0.500% of its length when it is stretched with a tension of 20.0 N. What is the Young's modul
n200080 [17]

Answer:

(B) 1.41 x 10^{10} N/m^{2}

Explanation:

diameter of wire (d) = 0.6 mm = 0.0006 m

radius of wire (r) = 0.0006/2 = 0.0003 m

tension (force F) = 20 N

percentage strain = 0.5 %

what is the Young's modulus?

Young's modulus = \frac{stress}{strain}

where

  • stress = force/area

        stress = \frac{force}{πr^{2}}

        stress = \frac{20}{πx0.0003^{2}}

        stress =70735530.3 N/m^{2}

  • strain = percentage strain ÷ 100

        strain = 0.5 ÷ 100 = 0.005

therefore Young's modulus = \frac{stress}{strain} =\frac{70735530.3}{0.005} = 1.41 x 10^{10} N/m^{2}

3 0
3 years ago
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