Answer:
83000 m/s
Explanation:
Using
F = Bqv....................... Equation 1
Where F = Force experienced by the charge, B = magnetic field q = charge of the particle, v = speed of the particle.
make v the subject of the equation
v = F/Bq.................... Equation 2
Given: q = 5.2×10⁻¹⁹ Coulombs, F = 9.5×10⁻¹⁵ Newtons, B = 2.2×10⁻¹ Tesla
Substitute into equation 2
v = 9.5×10⁻¹⁵ /(5.2×10⁻¹⁹×2.2×10⁻¹)
v = 8.3×10⁴ m/s
v = 83000 m/s
- momentum
- Yes, if the elephant is standing still.
- Fullback
- impulse acting on it.
- 2.25 N∙s
- A cannon firing.
- Inelastic
- it stays the same
- When the cue ball contacts the other balls, momentum is transferred causing them to gain momentum and speed.
- less than 3 m/s
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Answer:
The coil radius of other generator is 5.15 cm
Explanation:
Consider the equation for induced emf in a generator coil:
EMF = NBAω Sin(ωt)
where,
N = No. of turns in coil
B = magnetic field
A = Cross-sectional area of coil = π r²
ω = angular velocity
t = time
It is given that for both the coils magnetic field, no. of turn and frequency is same. Since, the frequency is same, therefore, the angular velocity, will also be same. As, ω = 2πft.
Therefore, EMF for both coils or generators will be:
EMF₁ = NBπr₁²ω Sin(ωt)
EMF₂ = NBπr₂²ω Sin(ωt)
dividing both the equations:
EMF₁/EMF₂ = (r₁/r₂)²
r₂ = r₁ √(EMF₂/EMF₁)
where,
EMF₁ = 1.8 V
EMF₂ = 3.9 V
r₁ = 3.5 cm
r₂ = ?
Therefore,
r₂ = (3.5 cm)√(3.9 V/1.8 V)
<u>r₂ = 5.15 cm</u>
Answer:
Isentropic compression in a pump, Constant heat addition in a boiler, Isentropic expansion in a turbine, constant heat rejection in a condenser
Explanation:
Ideal rankine cycle schematic diagram and T-S diagram is shown in below figure
The process 1-2 is isentropic compression is taking place in pump.
The process 2-3 is constant heat addition, heat addition takes places at boiler.
The process 3-4 is isentropic expansion, is taking place is turbine.
The process 4-1 is constant heat rejection , takes place in condenser.
Answer:
Average force on the football = 168.82 N
Explanation:
Force = Mass x Acceleration
F = ma
Mass, m = 0.41 kg
We have equation of motion, v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = 21 m/s
Time, t = 0.051 s
Substituting
21 = 0 + a x 0.051
a = 411.76 m/s²
Substituting in force equation,
F = ma = 0.41 x 411.76 = 168.82 N
Average force on the football = 168.82 N