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Galina-37 [17]
3 years ago
10

What are 2 things that a ROOT does for plants?

Chemistry
2 answers:
insens350 [35]3 years ago
6 0
Supply's the water and keep it in the ground
Zanzabum3 years ago
5 0
A couple of things they do are
1. Roots absorb nutrients and water from the surrounding soil
2. Anchors the plant to the ground

Hope that helps :D

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19. Which of the following chemical equations represents
Lesechka [4]

Answer:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)

Explanation:

<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.

The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).

The chemical equation that represents this combustion is:

  • C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)

Once you balance it, you get:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

        Left side           Right side

C         3                          3

H         8                          4×2 = 8

O        5×2 = 10               3×2 + 4 = 10

That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected

6 0
3 years ago
Convert 254 ml in kg
lions [1.4K]
It is 0.0254

Hope that helps
3 0
4 years ago
Difference between cold process soap making and hot process soap making​
stepladder [879]

Answer:

Unlike cold process soap, the essential oils or fragrance/additives are added after gel phase. ... Cold process soap heats from the inside out, while hot process soap heats from the outside in. Unlike cold process soap, that lasts for 4-6 weeks, hot process soap can be used immediately after it hardens.

Explanation:

hope it helps you

7 0
3 years ago
Find the energy of the photon if the frequency is 1.97 × 10^8 s^-1
enot [183]
E=hv
=6.625×10^-34Js^-1×1.97×10^8s^-1
Cancel sec inverse.
=13.05×10^-26.

7 0
3 years ago
The combustion of 44.45 grams of a hydrocarbon gas mixture releases 2,649 kJ of heat. How much energy, in kWh, will the combusti
Naddika [18.5K]

Explanation:

It is given that 44.45 g of hydrocarbon gas produces 2649 kJ or 2649 \times 10^{3} J of heat.

Also here, 1 lb = 453.592 g.

Therefore, amount of energy released by 453.592 g of hydrocarbon gas will be calculated as follows.

              \frac{2649 \times 10^{3} J \times 453.592 g}{44.45 g}

             = 27.03 \times 10^{6} J

It is known that 1 J = 2.778 \times 10^{-7} Kwh.

Hence, 27.03 \times 10^{6} J = 27.03 \times 10^{6} J \times 2.778 \times 10^{-7} Kwh/J

                              = 7.508 Kwh

Thus, we can conclude that the combustion of exactly one pound of this hydrocarbon gas produce 7.508 Kwh energy.

3 0
3 years ago
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