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sesenic [268]
3 years ago
10

What gas is necessary for combustion to take place

Chemistry
2 answers:
madreJ [45]3 years ago
6 0
Oxygen for complete combustion
Nadusha1986 [10]3 years ago
6 0

Answer:

oxygen

Explanation:

three thing are required in proper combustional before ignition combustionb take place heat ,oxygen ,fuel

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A balloon moves vertically upward at
Usimov [2.4K]

Answer:

B. Velocity

Explanation:

The answer is Velocity because the def of velocity is the rate of constant speed in a given direction. I hope this helps, have a good night.

6 0
3 years ago
The universe is made up of ____
vladimir2022 [97]
The correct should be A. thousands of galaxies
7 0
3 years ago
Read 2 more answers
How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)
polet [3.4K]

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then <u>state a rule of three</u>:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And <u>solve for X</u>:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
7 0
3 years ago
When a hydrochloric acid solution is combined with
adoni [48]

Answer:

HCl(aq) + KOH(aq --> KCl(aq) + H₂O(l)

Explanation:

4 0
3 years ago
2) Calculate the percent composition of each element in Mgso,
iogann1982 [59]

Answer:

2)

\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%

3)

\% Ag=93.1\%\\\\\% O=6.9\%

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%

Best regards!

7 0
3 years ago
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