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3 years ago

Match the following

Chemistry

1 answer:

Ket [755]3 years ago

4 0

Answer:

Ai --> Bii

Aii --> Bi

Aiii --> Bv

Aiv --> Biii

Av --> Biv

Explanation:

For Ai, naphthalene sublimes directly from a solid to gas when heated at around 80 degree Celsius.

For Aii, Ozone has a molecular formula of O₃.

For Aiii, weeds are normally considered as "unwanted" plants. Many people may consider using herbicides to clear the weeds in their gardens.

For Aiv, filtration is a physical method for separating solid and liquid from a mixture. A filter paper is normally used, in which the complex structure of the paper only allows fluid to pass through it, but not the solid ones. The solid left behind on the filter paper is called "residue".

For Av, photosynthesis is a chemical reaction that occurs in the leaves of a plant, which produces food for plants to survive. Carbon dioxide, water and light are required for photosynthesis to take place.

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jeyben [28]

Answer: The correct answer is in chemical bonds

Explanation:

When coal is burnt, these components burn and release energy. The energy released is by the chemical reaction between the constituents and oxygen

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3 years ago

Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)

Blizzard [7]

Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?

8 0

3 years ago

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O

madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9$ at 1,000 K

Calculate Kc for the reaction $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

<u>Answer:</u> The value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

<u>Explanation:</u>

The given chemical equations follows:

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c$

We need to calculate the equilibrium constant for the equation, which is:

$2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c'=(K_c)^2$

We are given:

$K_c=4.4\times 10^9$

Putting values in above equation, we get:

$K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}$

Hence, the value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

3 0

3 years ago

Element R and Element Q have the same number of valence electrons. These elements have similar chemical behavior, but element R

I am Lyosha [343]

Answer:

I dont now because I am in 6 class

7 0

3 years ago

An iron nail rusts when exposed to oxygen. According to the following reaction, how many moles of iron(III) oxide will be formed

Zigmanuir [339]

Answer:

0.453 moles

Explanation:

The balanced equation for the reaction is:

2Fe(s) + 3O2(g) ==> 2Fe2O3

From the equation, mass of O2 involved = 16 x 2 x 3 = 96g

mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2

= 100g

Therefore 96g of O2 produced 100g of Fe2O3

32.2g of O2 Will produce 100x32.2/96

= 33.54g of Fe2O3

Converting it to mole using number of mole = mass/molar mass

but molar mass of Fe2O3 = 26 + (16 X 3)

= 74g/mole

Therefore number of mole of 33.54g of Fe2O3 = 33.54/74

= 0.453 moles

5 0

3 years ago

Match the following ​

Match the following