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harkovskaia [24]
3 years ago
5

A 35-ft³ rigid tank has propane at 25 psia, 540 R and is connected by a valve to another tank of 20 ft³ with propane at 40 psia,

700 R. The valve is opened and the two tanks come to a uniform state at 580 R.
What is the final pressure?

Engineering
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

final pressure = 200KPa or 29.138psia

Explanation:

The detailed step by step calculations with appropriate conversion factors applied are as shown in the attachment.

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For the same cross-sectional area, which column provides the higher buckling load: a circular bar or a circular tube?
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Now for better understanding lets take an example

Lets take

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So from we can say that both tubes have equal cross sectional area.

We know that buckling load is given as P = \dfrac{\pi ^2EI}{L_e^2}      

If area moment of inertia(I) is high then buckling load will be high.

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For circular bar I = \dfrac{\pi }{64}D^4  

Now by putting the values

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So we can say that for same cross sectional area the  area moment of inertia(I) is high for tube as compare to bar.So buckling load  will be higher in tube as compare to bar.

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