A 35-ft³ rigid tank has propane at 25 psia, 540 R and is connected by a valve to another tank of 20 ft³ with propane at 40 psia,
700 R. The valve is opened and the two tanks come to a uniform state at 580 R.
What is the final pressure?
What is the final pressure?
1 answer:
You might be interested in
Answer:
The answer is 27.69 [psi]
Explanation:
(Barinly´s editor seem to not be working properly so please see attachment)
We know that:
Where:
- σ => Stress in the material
- Pin => Internal Pressure
- Din => Internal diameter
- t => Thickness
Since we know that thre Stress is directly proportional to Pin and Din but inversely proportional to thickness, we need to add a proportionality constant "k" to our equation to make it complete:
We also know that the Stress is 100 [psi] when Pin is 25 [psi], Din is 5 [in] and thickness is .75 [in], using this values we can solve for k:
thus k = .6
Now all we need to know is use the same equation but using the new parameters: Pin = 15 [psi], Din = 2 [in] and t= .65 [in]
The stress is 27.69 [psi]
