A 35-ft³ rigid tank has propane at 25 psia, 540 R and is connected by a valve to another tank of 20 ft³ with propane at 40 psia,
700 R. The valve is opened and the two tanks come to a uniform state at 580 R.
What is the final pressure?
What is the final pressure?
1 answer:
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Answer:
The time required is 10.078 hours or 605 min
Explanation:
The formula to apply here is ;
K=(d²-d²₀ )/t
where t is time in hours
d is grain diameter to be achieved after heating in mm
d₀ is the grain diameter before heating in mm
Given
d=5.5 × 10^-2 mm
d₀=2.4 × 10^-2 mm
t₁= 500 min = 500/60 =25/3 hrs
t₂=?
n=2.2
First find K
K=(d²-d²₀ )/t₁
K={ (5.1 × 10^-2 mm)²-(2.4 × 10−2 mm)² }/ 25/3
K=(0.051²-0.024²) ÷25/2
K=0.000243 mm²/h
Re-arrange equation for K ,to get the equation for d as;
d=√(d₀²+ Kt) where now t=t₂
Answer:
Explanation:
From the information given:
Life requirement = 40 kh = 40
Speed (N) = 520 rev/min
Reliability goal = 0.9
Radial load = 2600 lbf
To find C10 value by using the formula:
where;
The Weibull parameters include:
∴
Using the above formula:
Recall that:
1 kN = 225 lbf
∴