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3 years ago

Date the law of conversation of energy

Physics

1 answer:

Margaret [11]3 years ago

3 0

Answer:

In its most compact form, it states: matter is neither created nor destroyed. In 1842, Julius Robert Mayer discovered the Law of Conservation of Energy.

Explanation:

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A kayak took 5 hours to finish its trip on a river. If it traveled at an

snow_tiger [21]

It would mean that it was a 90 mile trip. All you would have to do is multiply 18 by 5

5 0

3 years ago

A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3 km/h.

Amanda [17]

Answer:

$F_{1}=\frac{1}{5}F_{2}$ or $F_{2}=5F_{1}$

In other words, $F_{1}$ is one fifth of $F_{2}$ or $F_{2}$ is five times as big as $F_{1}$

Explanation:

In order to solve this problem we must start by sketching the situation (refer to the attached picture).

When the ship is pulled only by force 1, it will change its speed by 3km/hr in 10 seconds. So in order to use these values we need to either turn the km/hr in km/s or turn the seconds to hours. Let's turn the seconds to hours:

$10s*\frac{1hr}{3600s}=\frac{1}{360} hr$

so we can now use the acceleration formula to find the acceleration of the boat so we get:

$a=\frac{\Delta v}{\Delta t}$

which will give us an accceleration of:

$a=\frac{3km/hr}{\frac{1}{360}hr}=1080km/hr^{2}$

once we got the acceleration we can for sure say taht:

$F_{1}=ma=m*1080\frac{km}{hr^{2}}$

Now, if we take a look at the second drawing we can see that the resultant force applied to the boat is found by adding the two forces, force one and force two, so we get:

$F_{1}+F_{2}=ma$

in this case the acceleration changes because the change in velocity is of 18km/hr in the same 10 seconds, so we get that:

$a=\frac{\Delta v}{\Delta t}$

$a=\frac{18km/hr}{\frac{1}{360}hr}=6480km/hr^{2}$

so we can say that:

$F_{1}+F_{2}=m*6480km/hr^{2}$

we can substitute the first force into this equation so we get:

$m*1080km/hr^{2}+F_{2}=m*6480km/hr^{2}$

and solve for the second force, so we get:

$F_{2}=m*6480km/hr^{2}-m*1080km/hr^{2}$

which yields:

$F_{2}=m*5400km/hr^{2}$

Now we can compare theh two forces, force 1 and force 2 by dividing them:

$\frac{F_{1}}{F_{2}}=\frac{m*1080km/hr^{2}}{m*5400km/hr^{2}}$

which yields:

$\frac{F_{1}}{F_{2}}=\frac{1}{5}$

when solving for the first force we get:

$F_{1}=\frac{1}{5}F_{2}$

which tells us that the second force is one fifth of the first force.

and when solving for the second force we get that:

$F_{2}=5F_{1}$

which means that the second force is 5 times as big as the first force.

8 0

3 years ago

An atom has seven protons, eight neutrons, and six electrons. What type of electrical charge does it possess?

Crank

Answer:

positive

Explanation:

No. of positive charge= 7

No.of negative charge = 6

so 7 - 6 = 1 positive charge

7 0

3 years ago

A man seeking to set a world record wants to tow a 101,000-kg airplane along a runway by pulling horizontally on a cable attache

NemiM [27]

Answer:

6.19 x $10^{-3}$ m/ $s^{2}$

Explanation:

For this exercise we need to sum the forces on the y-axis and x-axis as follows:

∑ $F_{y}$ = N - mg = m. $a_{y}$ = 0

From the exercise, we deduce there is no motion in y-axis, so:

N = mg

Then for x-axis we have:

∑ $F_{x}$ = H - $f^{s}$ = m. $a_{x}$ = 0

Now, from the exercise we deduce that we are looking for the greatest static friction which means to have the maximun static friction to start moving, so at this point the acceleration is zero, so we can find horizontal force (H), which then will act in the airplane to move it. Therefore we have:

H = $f^{s}$ = $f^{sma_{x} }$ = $u_{s}$ N = $u_{s}$ mg