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Evgen [1.6K]
3 years ago
10

Date the law of conversation of energy

Physics
1 answer:
Margaret [11]3 years ago
3 0

Answer:

In its most compact form, it states: matter is neither created nor destroyed. In 1842, Julius Robert Mayer discovered the Law of Conservation of Energy.

Explanation:

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I need help with this problem :(​
Reil [10]

Answer:

it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.

7 0
3 years ago
A student at the top of a building of height h throws one ball upward with a speed of vi and then throws a second ball downward
Agata [3.3K]

Answer:

The velocity of the one thrown up will be the same as the second one

Explanation:

They will fall and hit the ground at the same time although they have the same velocity because object one although has double height it has initial velocity of zero

5 0
3 years ago
The effects of force on gravity is more noticeable when the object is_____
Vsevolod [243]

Answer:

Gravity only becomes noticeable when there is a really massive object like a moon, planet or star. We are pulled down towards the ground because of gravity. The gravitational force pulls in the direction towards the centre of any object.

8 0
3 years ago
A basketball with mass of 0.8 kg is moving to the right with velocity 6 m/s and hits a volleyball with mass of 0.6 kg that stays
IceJOKER [234]

Answer:

26.67 m/s

Explanation:

From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.

p=mv where p is momentum, m is the mass of object and v is the speed of the object

Initial momentum

The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

p_i= m_bv_b+m_vv_v=8*6+0.6*0=48 Kg.m/s

Final momentum

p_f= m_bv_b+m_vv_v=8*4+0.6*v_v=32+0.6v Kg.m/s\\32+0.6v_v=48\\0.6v=16\\v_v=16/0.6=26.66666667\approx 26.67 m/s

4 0
3 years ago
If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what wo
Elena L [17]

Answer: The question is incomplete or some details are missing. Here is the complete question ; (a) The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.55 m/s2 for 4.05 s, making straight skid marks 63.0 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree? m/s

(b) What If? If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2

a ) With what speed (in m/s) does the car then strike the tree? m/s = 4.3125m/s

b) then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2 = -5.696m/s2

Explanation:

The detailed steps and calculation is as shown in the attached file.

6 0
4 years ago
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