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4 years ago

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There are sparrows and cardinals that feed at Mrs. Sims bird feeder. The ratio of sparrows to cardinals is 3:1. There are at lea

st 7, but less than 11 sparrows that eat at Mrs. Sims bird feeder. Put an S in the grid below to show the number of sparrows and a C to show the number of cardinals. There may be extra squares. (See attachment)

1 answer:

saveliy_v [14]4 years ago

8 0

Answer:

Please find the grid of Sparrows and Cardinals below.

Step-by-step explanation:

Ratio 3:1 of Sparrows to Cardinals

There are at least 7, but less than 11 sparrows that eat at Mrs. Sims bird feeder

Let's build the grid for sparrows and cardinals, this way:

<u>Sparrows = 7 - 8 - 9 - 10 - 11</u>

<u>Cardinals = 2 - 3 - 3 - 3 - 4</u>

For calculating the number of cardinals we use the ratio 3:1 and round the number of cardinals to the next whole number.

<u>Number of sparrows 7 to 11</u>

<u>Number of cardinals 2 to 4</u>

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3 years ago

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The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

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<u>To Find :</u>

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<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

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$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

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To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

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$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

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$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

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$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

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$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

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$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

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$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

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