Question

-g A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end (Fig. E11.11). The diving board is of uniform cross section and weighs 280 N. Find (a) the force at the support point and (b) the force at the left-hand end.

Answer 1

Answer:

Explanation:

Let the force at the support end is R and at the left end is F.

According to the equilibrium condition

F + R = 280 + 500

F + R = 780 .... (1)

Take moments about G.

F x 1.5 + R x 0.5 = 500 x 1.5

3F + R = 1500 .... (2)

Subtract equation (1) from equation (2), we get

2F = 1500 - 780

F = 360 N

R = 780 - 360

R = 420 N

(a) Force at support is 420 N

(b) force at the left end is 360 N.