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3 years ago

There are only 2 GENDERS and it proven with science

Physics

1 answer:

VikaD [51]3 years ago

6 0

Answer:

https://young.scot/get-informed/national/gender-identity-terms

Explanation:

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What is the displacement of the runner in 4 laps? *<br> 2 point

Serhud [2]

Answer:

There is no displacement.

Explanation:

Because the runner is running laps and returning to the original place, there is no displacement as displacement is relative to the change in location from the original position.

Hope this helps. . .

ly UwU

3 0

3 years ago

What I Know True or False. Read each statement carefully. Identify whether the statement is true or false. Write your answer on

timofeeve [1]

Answer:

1. False

2. True

3. True

4. True

5. True

6. False

7. True

8. False

9. False

10. True

11. True

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7 0

3 years ago

Read 2 more answers

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the sl

77julia77 [94]

Answer:

The phase difference between waves 31.7 rad

Explanation:

Given :

Wavelength $\lambda = 540 \times 10^{-9}$ m

Separation between two slit $d = 0.370 \times 10^{-3}$ m

Angle $\theta =$ 25°

From the formula of phase difference,

$\delta = \frac{2\pi d }{\lambda} \sin \theta$

Where $\delta =$ phase difference

$\delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25$

$\delta = 31.7$ rad

Therefore, the phase difference between waves 31.7 rad

5 0

3 years ago

Which subatomic particles will you add or remove to change the mass of an atom

user100 [1]

B. because protons and neutron are the sum of atomic mass of an element

4 0

3 years ago

Consider a 30-cm-diameter hemispherical enclosure. The dome is maintained at 600 K, and heat is supplied from the dome at a rate

SIZIF [17.4K]

Answer:

$\epsilon_2=0.098$

Explanation:

Diameter $d=30cm=0.3m$

Temperature $T=600k$

Rate of supply $r=65W$

Emissivity of base surface $\in_b =0.55$

Temperature at base $T_b=400k$

Generally the equation for Area of base surface is mathematically given by

$A_b=\frac{\pi}{4}d^2$

$A_b=\frac{\pi}{4}0.3^2$

$A_b=0.0707m^2$

Generally the equation for Area of Hemispherical dome is mathematically given by

$A_h=\frac{\pi}{2}d^2$

$A_h=\frac{\pi}{2}0.3^2$

$A_h=0.1414m^2$

Since base is a flat surface

$F_{11}+F_{12}=1$

$F_{11}=0$

Therefore

$F_{12}=1$

$A_b=0.0707m^2$

Generally the equation for Net rate of radiation heat transfer between two surfaces is mathematically given by

$Q_{21}=-Q_{12}$

$Q_{21}=\frac{\sigma(T_1^4-T_2^4)}{\frac{1-\epsilon}{A_b\epsilon_1} +\frac{1}{A_bF_{12}} +\frac{1-\epsilon_2}{A_h*\epsilon_2} }$

Where

$\sigma=5.67*10^{-8}$

Therefore

$65=\frac{(5.67*10^{-8}(400^4-600^4))}{\frac{1-0.55}{0.0707*0.55}+\frac{1}{0.0707}+\frac{1-\epsilon_2}{0.1414*\epsilon_2}}$

$\epsilon_2=0.098$

$\epsilon_2 \approx 0.1$

Therefore the emissivity of the dome is

$\epsilon_2=0.098$

3 0

3 years ago