A uniform magnetic field passes through a horizontal circular wire loop at an angle 17.3 ° 17.3° from the normal to the plane of
1 answer:
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Answer:
Explanation:
Complete Question:
A.Compute no of electrons you expect to count if silicon detector is struck with a 1.04 Mev gamma ray produced in a decay of 136 Cs nucleus.
b.Explain counting of electrons is more precise as the detector is cooled well below room temperature
Answer:
a.
Gamma ray energy =
photon strikes the surface excite the electrons to move from valence band to conduction band where then counted by detector.
energy gap between valence band and conduction band in case of silicon = 1.1 eV
The minimum amount of energy required is 1.1 ev
minimum number of electron counted is =
=
b.
In the case of semi conductors
forbidden energy gap in inversely proportional to temperature
with decrease in temperature forbidden energy gap increases,hence electrons jumping from valence band to conduction band decreases and hence counting by detector decreases
Answer:
a-1 Graph is attached. The relation is linear.
a-2 The corresponding height for 68 kPa Pressure is 7.54 m
a-3 The corresponding weight for 68 kPa Pressure is 1394726kg
b The original height of the column is 5.98 m
Explanation:
Part a
a-1
The graph is attached with the solution. The relation is linear as indicated by the line.
a-2
By the equation
Here
- P is the pressure which is given as 68 kPa.
- ρ is the density of the oil whose SG is 0.92. It is calculated as
- g is the gravitational constant whose value is 9.8 m/s^2
- h is the height which is to be calculated
So the height of column is 7.54m
a-3
By the relation of volume and density
Here
- ρ is the density of the oil which is 920 kg/m^3
- V is the volume of cylinder with diameter 16m calculated as follows
Mass is given as
So the mass of oil leading to 68kPa is 1394726kg
Part b
Pressure variation is given as
Now corrected pressure is as
Finding the value of height for this corrected pressure as
The original height of column is 5.98m
