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Softa [21]
3 years ago
8

A uniform magnetic field passes through a horizontal circular wire loop at an angle 17.3 ° 17.3° from the normal to the plane of

the loop. The magnitude of the magnetic field is 2.55 T 2.55 T , and the radius of the wire loop is 0.250 m 0.250 m . Find the magnetic flux Φ Φ through the loop.
Physics
1 answer:
umka21 [38]3 years ago
7 0

Answer:

4.78 × 10⁻³ T.m²

Explanation:

The expression for the magnetic flux is given by

∅ = BAcosФ

where B = magnetic field strength

A = Area of circular loop = πr²

r = radius of the wire loop

substitute πr² for A in the first equation

∅ = Bπr²cosФ

∅ = 2.55 × 3.14 × 0.025² × cos 17.3°

∅ = 4.78 × 10⁻³ T.m²

OR

0.00478 T.m²

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Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

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Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

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f = frequency of wave = \frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz

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5 0
3 years ago
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Doss [256]

Answer:

4.6×10^-7 m or 0.46nm

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From

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λ= hc/Wo

λ= 6.6×10^-34 × 3×10^8/4.30×10^-19

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5 0
3 years ago
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Answer:

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Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

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Answer:

 ,   l l. l

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frozen [14]
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4 0
3 years ago
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