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Shkiper50 [21]
3 years ago
13

A pelican flying drops a fish from a height of 8.1 m. The fish travels 9.3 m horizontally before it hits the ground. The pelican

’s speed was
Physics
1 answer:
masya89 [10]3 years ago
7 0
Using kinematics: 8.1 = 1/2(9.8)(t^2),
t = 1.2857 s.
Horizontal distance x travelled is x = vhorizontal * t, so 9.3 = v*1.2857, or v= 7.233 m/s horizontally.
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Mercury is in the 80th position in the periodic table. How many protons does it have?
aalyn [17]
Mercury has 80 protons.
4 0
3 years ago
Read 2 more answers
A 91-kg astronaut and a 1300-kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, givi
WARRIOR [948]

Answer:

18.2145 meters

Explanation:

Using the conservation of momentum, we have that:

m1v1 + m2v2 = m1'v1' + m2'v2'

m1 = m1' is the mass of the astronaut, m2=m2' is the mass of the satellite, v1 and v2 are the inicial speed of the astronaut and the satellite (v1 = v2 = 0), and v1' and v2' are the final speed of the astronaut and the satellite. Then we have that:

0 + 0 = 91*v1' + 1300*0.17

v1' = -1300*0.17/91 = -2.4286\ m/s

The negative sign of this speed just indicates the direction the astronaut goes, which is the opposite direction of the satellite.

If the astronaut takes 7.5 seconds to come into contact with the shuttle, their initial distance is:

distance = 2.4286 * 7.5 = 18.2145\ meters

8 0
3 years ago
"Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swin
Bingel [31]
The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

<span>using v and Ti computed above.</span>
3 0
3 years ago
The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medi
adoni [48]

Answer:

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), F_v = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}

Take the ratio of the two forces;

\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N

Therefore, the value of new coulomb force is 1.43 N.

5 0
3 years ago
Please help if you have the time
Alex777 [14]

We know, length of segment wave is half the wavelength .

Let, wavelength of wave is \lambda.

So, length of segment will be \dfrac{\lambda}{2} .

Now, it is given that the string vibrates in four segments.

So,

L = 4\times \dfrac{\lambda}{2}\\\\L = 2\lambda\\\\\lambda = 1\ m

Speed can be given by :

speed = wavelength \times frequency\\\\speed = 1\times 120\  m/s\\\\speed = 120\ m/s

Therefore, the wave speed in the string is 120 m/s.

6 0
2 years ago
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