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stealth61 [152]
3 years ago
13

As seen, any object with electric charge, stationary or moving, other than the charged object that created the field, experience

s a force in an electric field. Also, any object with electric charge, stationary or moving, can create an electric field. Similarly, an electric current or a moving electric charge, other than the current or charge that created the field, experiences a force in a magnetic field, and an electric current created a magnetic field.
a. To understand how a moving charge can also create a magnetic field, consider a particle with charge q moving with velocity v. Define the position vector r = r. r leading from the particle to some location. Show that the magnetic field at that location is

B= µo/4π= qv x r/r^2

b. Find the magnitude of the magnetic field 1.05 mm to the side of a proton moving at 1.50 x 10^7 m/s.
c. Find the magnetic force on a second proton at this point, moving with the same speed in the opposite direction.
d. Find the electric force on the second proton

Physics
1 answer:
sammy [17]3 years ago
6 0

Answer:

The answer and explanation is in the attached file

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Find the dimension of volume​
BlackZzzverrR [31]

Answer:

L^3

Explanation:

7 0
3 years ago
during a workout, a football player pushes a blocking dummy a distance of 30 m. while pushing the dummy the same distance a seco
babymother [125]
Power=\frac{Work}{Time}=\frac{Force\times distance}{time}

If he wants to increase power, force must increase and decrease time.
8 0
4 years ago
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A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69
ra1l [238]

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

h = 198.0/cos(76.31)

h = 836.6 cm

3 0
4 years ago
What would be the weight of the moon if it were resting on the surface of the earth
kari74 [83]
We need to be careful here.
The calculation of the gravitational force between two objects
refers to the distance between their centers. 
The minimum possible distance between the Earth's and moon's
centers is the sum of their radii (radiuses).

Earth's radius . . . . .  6,360 km  =  6.36 x 10⁶ meters
Moon's radius . . . . .  1,738 km  =  1.738 x 10⁶ meters
Sum of their radii  =                      8.098 x 10⁶ meters

Also:
Earth's mass . . . . .  5.972 x 10²⁴ kg
Moon's mass . . . . .  7.348 x 10²²  kg
<span>
and now we're ready to go !

       Gravitational force = 

                   G  M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(</span><span>5.972 x 10²⁴ kg)(7.348 x 10²²  kg)/</span>(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³)      Newtons

=    (I get ...)        4.463 x 10²³ Newtons

That's almost exactly   10²³ pounds 

                           =  50,153,000,000,000,000,000 tons.     

Those are big numbers. 
All I can say is:  I wouldn't exactly call that "resting" on the surface".
7 0
3 years ago
Object a travels in the +x-direction before hitting a stationary object
Leto [7]
The object’s resultant angle of motion with the +x-axis after the collision is 47°

<span>From object A:
 
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
 
Now, we know, tan</span>Ф = \frac{y}{x}

⇒tanФ = \frac{6.2 × 10^4 }{5.7 × 10^4}

⇒tanФ = 1.088

⇒ Ф = tan^{-1} 1.088 
         =  47.4 ≈ 47

8 0
3 years ago
Read 2 more answers
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