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Dmitrij [34]
3 years ago
7

A 25-kilogram space probe fell freely with an acceleration of 2.0 m/s2 just before it landed on a distant planet. What is the we

ight of the space probe on that planet?
Physics
1 answer:
malfutka [58]3 years ago
8 0

the weight of the space probe on that planet is 50 N

To calculate the weight of the space probe, we use the formula below.

Formula:

  • W = mg

Where:

  • W = weight of the space probe on the planet
  • m = mass of the space probe
  • g = acceleration due to gravity.

From the question,

Given:

  • m = 25 kg
  • a = 2 m/s

Substitute these values into equation 1

  • W = 25(2)
  • W = 50 N.

Hence, the weight of the space probe on that planet is 50 N

Learn more about weight here: brainly.com/question/229459

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What are the difference between conductor and insulator? ​
Anvisha [2.4K]

Answer:

  • A conductor allows energy e.g. electric charge or heat to pass through it easily. While an insulator does not let electric current or heat to travel through it.
  • Insulators have strong molecular bonds. While molecular bonds are very weak in conductors.
  • Insulators have very low conductivity. While in conductors, it is very high.
  • Insulators have a very high resistance and therefore the electrons are held together very firmly. The conductors, on the other hand, have a very low resistance.
  • Insulators do not have any electric field, neither inside nor on the surface. While in conductors, it is found on the surface and continues to be zero in the inner part of the conductor.
5 0
3 years ago
Help me please I can't get the final step​
inna [77]

Answer:

\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

\displaystyle A=\frac{3}{2}B^mC^n

and the dimensions of each variable is:

A=L^2T^2

B=LT^{-1}

C=LT^2

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n

Operating:

L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)

L^2T^2=L^{m+m}T^{-m+2n}

Equating the exponents:

m+n=2

-m+2n=2

Adding both equations:

3n=4

Solving:

n=4/3

m=2-4/3=2/3

Answer:

\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}

6 0
3 years ago
4. How will you find the volume of an irregularly shaped object that would dissolve<br>in water?​
Dimas [21]
Um you should putting it in a object that it can fill then go from there
4 0
3 years ago
Read 2 more answers
One of the harmonics of a string fixed at both ends has a frequency of 52.2 Hz and the next higher harmonic has a frequency of 6
Angelina_Jolie [31]

Solution :

Frequency may be defined as the number of observation or number of waves that is taken in per unit time. The unit of frequency is Hertz or Hz.

It is given that :

Successive harmonic frequencies, f = 52.2 Hz

and f' = 60.9 Hz

Therefore, fundamental frequency, F = f' - f

                                                           F = 60.9 - 52.2

                                                          F = 8.7 Hz

Therefore the string which is fixed at both the ends forms all the harmonics.

6 0
2 years ago
WHOEVER GET IT RIGHT GETS 50 POINTS
AVprozaik [17]

Answer:

ANSWER BELOW I

                             I

                            V

Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in

m/s2

. For example, for Earth, 445 N = 45.4 × 9.8

m/s2

:Notice that the x-axis values will be gravity in

m/s2

, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).

3 0
4 years ago
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