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Nataliya [291]
3 years ago
10

Jill is making lemonade. She mixes together some water, lemon juice, and sugar. The lemonade is classified as a(n) _________. A)

compound B) element C) mixture D) solid
Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Hello, Thanks for making your post on brainly!

I would say the best answer is C)Mixture

A mixer is made by combining 2 or more elements, but your not making a new element. And there are no chemical reactions happening to make a new element.

Hope this helps. Have a great day.

umka2103 [35]3 years ago
6 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

A compound is defined as the substance which is made of different kinds of atoms. <u>For Example:</u> Water (H_2O) is made from hydrogen and oxygen atoms

An element is defined as the substance which is made of similar kind of atoms. All the atoms in an element have same atomic number.

Mixture is defined as the combination of two or more different pure substances where each pure substance retains its original chemical properties.

Solid is defined as the state of matter in which the particles are closely packed and does not have any space between them

We are given:

A lemonade is made by the combination of water, lemon juice and sugar. The combination of these substances leads to the formation of mixture.

Hence, the correct answer is Option C.

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Nault 25000L 250 our = 25000L 15040 8. How many grams of CaCl2 are needed to make 150.0 mL of a 0.500 M CF solution? (Note: CaCl
yuradex [85]

Answer:

You need 8,324 g of CaCl₂ yo make this solution

Explanation:

Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.

To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:

0,1500 L × \frac{0,500 mol}{L} = 0,075 CaCl₂ moles

Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:

0,075 CaCl₂ moles  × \frac{110,98 g}{mol} = 8,324 g of CaCl₂

So, you need <em>8,324 g of CaCl₂</em> to make 150,0 mL of a 0,500M solution

I hope it helps!

3 0
3 years ago
Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?
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1.5052g BaCl2.2H2O => 1.5052g / 274.25 g/mol = 0.0054884 mol
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<span>0.0054884 mol BaSO4 => 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4</span>
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