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Nataliya [291]
3 years ago
10

Jill is making lemonade. She mixes together some water, lemon juice, and sugar. The lemonade is classified as a(n) _________. A)

compound B) element C) mixture D) solid
Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Hello, Thanks for making your post on brainly!

I would say the best answer is C)Mixture

A mixer is made by combining 2 or more elements, but your not making a new element. And there are no chemical reactions happening to make a new element.

Hope this helps. Have a great day.

umka2103 [35]3 years ago
6 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

A compound is defined as the substance which is made of different kinds of atoms. <u>For Example:</u> Water (H_2O) is made from hydrogen and oxygen atoms

An element is defined as the substance which is made of similar kind of atoms. All the atoms in an element have same atomic number.

Mixture is defined as the combination of two or more different pure substances where each pure substance retains its original chemical properties.

Solid is defined as the state of matter in which the particles are closely packed and does not have any space between them

We are given:

A lemonade is made by the combination of water, lemon juice and sugar. The combination of these substances leads to the formation of mixture.

Hence, the correct answer is Option C.

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2.what is the purpose of the sodium sulfate? (1 pt) why did you rinse the sodium sulfate with an additional portion of methylene
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<h3>What is the purpose of the sodium sulfate?</h3>
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brainly.com/question/23509646

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4 0
1 year ago
How many electrons can the px atomic orbital subtype hold?
NemiM [27]
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8 0
3 years ago
139%
GaryK [48]

<u>Answer:</u>

The percent composition of this compound is 94%

<u>Explanation:</u>

The reaction can be formed as

2 \mathrm{Fe}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}

\frac{\text { Weight of } \mathrm{Cl}_{2}}{\text { 3* Molar Mass of } \mathrm{Cl}_{2}}=\frac{\text { Weight of } \mathrm{Fe}}{2 * \text { Molar Mass of Fe }}

\frac{\text { Weight of } \mathrm{Cl}_{2}}{3 *(2 * 35.5)}=\frac{3.56}{2 * 55.8}

\text { Weight of } C l_{2}=\frac{3.56 * 3 * 71}{2 * 55.8}=6.79 \mathrm{g}

\mathrm{n}\left(\mathrm{Cl}_{2}\right)=\mathrm{m}\left(\mathrm{Cl}_{2}\right) / \mathrm{M}\left(\mathrm{Cl}_{2}\right)=6.79 / 71=0.1 \mathrm{m}

\mathrm{n}(\mathrm{Fe})=\mathrm{m}(\mathrm{Fe}) / \mathrm{M}(\mathrm{Fe})=3.56 / 55.8=0.06 \mathrm{m}

Based on no. of iron reacted,  

\mathrm{n}(\text { moles of } \mathrm{Fe})=\mathrm{n}\left(\text { moles of } \mathrm{FeCl}_{3}\right)

n = m/M

\mathrm{m}\left(\mathrm{FeCl}_{3}\right)=\mathrm{n}^{*} \mathrm{M}=0.06^{*} 162.5=9.75 \mathrm{g}

% composition ofFeCl_3  

=  (9.75 / 10.39)^{*} 100

= 94%

6 0
3 years ago
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