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3 years ago

Question 3 of 10

Chemistry

2 answers:

Kruka [31]3 years ago

7 0

The awnser is b water freezing

miss Akunina [59]3 years ago

6 0

Answer:

the answer is B

Explanation:

B is the answer

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The tiny magnetic effect of atoms within a domain is due to electrons that are _____. paired and spinning in opposite directions

VLD [36.1K]

The tiny magnetic effect of atoms within a domain is due to electrons that are unpaired and spinning in the same direction.

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3 years ago

Read 2 more answers

Suppose 'A' is a liquid aromatic compound with molecular weight 78 and burns with sooty flame. a.Give the name of the compound '

Oliga [24]

Aromatic compounds are compounds that contain carbon-carbon multiple bonds.

The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.

So,

(CH)n = 78

where n is the number of each atom present.

(12 +1)n = 78

n = 78/13

n = 6

The molecular formula of the compound is C6H6

When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.

When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.

brainly.com/question/24305135

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3 years ago

Correct possible values of l for n = 4?

Kamila [148]

Answer:

0,1,2,3

Explanation:

for the given value of n , l = 0 to n-1

so if n = 4

l = 0 to 4-1

6 0

3 years ago

How much does a gallon of water WEIGH?

elixir [45]

A gallon of water weighs 8.34 pounds

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4 years ago

Consider a galvanic cell based on the reaction Al^3+_(aq) + Mg_(s) rightarrow Al_(s) + Mg^2+ _(aq) The half-reactions are Al^3+

grin007 [14]

Answer: The standard cell potential of the cell is -0.71 V

Explanation:

The half reactions follows:

Oxidation half reaction: $Mg\rightarrow Mg^{2+}+2e^-;E^o_{Mg^{2+}/Mg}=-2.37V$ ( × 3)

Reduction half reaction: $Al^{3+}(aq.)+3e^-\rightarrow Al(s);E^o_{Al^{3+}/Al}=-1.66V$ ( × 2)

The balanced cell reaction follows:

$2Al^{3+}(aq.)+3Mg(s)\rightarrow 2Al(s)+3Mg^{2+}(aq.)$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation, we get:

$E^o_{cell}=-2.37-(-1.66)=-0.71V$

Hence, the standard cell potential of the cell is -0.71 V

8 0

3 years ago