At temperature 332.13 °C
<h3>Further explanation</h3>
Charles's Law stated that :
When the gas pressure is kept constant, the gas volume is proportional to the temperature

T₁ = 89 °C=89+273=362 K
V₁ = 0.67 L
V₂ = 1.12 L

The significance of melting points are
- it gives us a idea about inter molecular force which binds the particles together.
- at melting point the solid and liquid states exist in equilibrium.
<h3>What is melting point?</h3>
The melting point is the temperature at which a given substance change its physical state from solid to liquid. At this point solids and liquids exist at equilibrium. Melting point of a substance depends on pressure. The melting point of ice increases when pressure decreases. Melting point of a substance decreases by the presence of impurities in it. so you increase or decrease the melting point on any substance by adding more impurities. Ionic bonds, shape and size of molecules are some other factors that affect the melting point.
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The expected final temperature of the block, given that 586 J of heat were added to it is 55.5 °C
<h3>How to determine the final temeprature</h3>
We'll begin by obtaining the change in the temperature of the block. This can be obtained as follow:
- Specific heat capacity of block (C) = 0.240 J/gºC
- Heat added (Q) = 586 J
- Mass of block (M) = 80.0 g
- Change in temperature (ΔT) =?
Q = MCΔT
Divide both sides by MC
ΔT = Q / MC
ΔT = 586 / (80.0 × 0.240)
ΔT = 586 / 19.2
ΔT = 30.5 °C
Finally, we shall determine the final temperature of the block. This can be obtained as follow:
- Initial temperature (T₁) = 25 °C
- Change in temperature (ΔT) = 30.5 °C
- Final temperature (T₂) = ?
ΔT = T₂ – T₁
30.5 = T₂ – 25
Collect like terms
T₂ = 30.5 + 25
T₂ = 55.5 °C
Thus, from the calculation made above, we can conclude that the final temperature is 55.5 °C
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<h3>
Answer:</h3>
812 kPa
<h3>
Explanation:</h3>
- According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
- Mathematically,

At varying pressure and volume;
P1V1=P2V2
In this case;
Initial volume, V1 = 2.0 L
Initial pressure, P1 = 101.5 kPa
Final volume, V1 = 0.25 L
We are required to determine the new pressure;

Replacing the known variables with the values;

= 812 kPa
Thus, the pressure of air inside the balloon after squeezing is 812 kPa
<em>Answer:</em>
- 0.052301 km have 5 significant figure
- 400 cm have 1 significant figure
- 50.0 m have 3 significant figure
- 4500.01 ml have 6 significant figure
<em>Explanation:</em>
According to rules of significant figure
0.052301 km have 5 significant figure:
- Zero to the left of the first non zero digit not significant.
- Zero between the non zero digits are significant.
<em>400 cm have 1 significant figure:</em>
- Trailing zeros are not significant in numbers without decimal points.
<em>50.0 m have 3 significant figure:</em>
- Trailing zeros are significant in numbers when there is decimal points.
<em>4500.01 ml have 6 significant figure:</em>
- Zero between the non zero digits are significant.